Hydraulics and Fluid Mechanics in ME In reaction turbine, draft tube is used To transport water downstream without eddies To convert the kinetic energy to flow energy by a gradual expansion of the flow cross-section For safety of turbine To increase flow rate To transport water downstream without eddies To convert the kinetic energy to flow energy by a gradual expansion of the flow cross-section For safety of turbine To increase flow rate ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The power developed by a turbine is (where H = Head of water under which the turbine is working) Directly proportional to H1/2 Inversely proportional to H1/2 Directly proportional to H3/2 Inversely proportional to H3/2 Directly proportional to H1/2 Inversely proportional to H1/2 Directly proportional to H3/2 Inversely proportional to H3/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The time oscillation of a floating body with increase in meatcentric height will be Lower/higher depending on weight of body Lower Higher Same Lower/higher depending on weight of body Lower Higher Same ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The property of fluid by virtue of which it offers resistance to shear is called adhesion cohesion viscosity surface tension adhesion cohesion viscosity surface tension ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The force exerted by a moving fluid on an immersed body is directly proportional to the rate of change of momentum due to the presence of the body. This statement is called Newton's law of resistance Newton's law of viscosity Newton's law of motion Newton's law of cooling Newton's law of resistance Newton's law of viscosity Newton's law of motion Newton's law of cooling ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] ANSWER DOWNLOAD EXAMIANS APP
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