Hydraulics and Fluid Mechanics in ME Low specific speed of turbine implies it is Propeller turbine Impulse turbine Any one of the above Francis turbine Propeller turbine Impulse turbine Any one of the above Francis turbine ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Euler's equation in the differential form for the motion of liquids is given by ρ.dp - g.dz + v.dv = 0 dp/ρ + g.dz + v.dv = 0 ρ.dp + g.dz + v.dv = 0 dp/ρ - g.dz + v.dv = 0 ρ.dp - g.dz + v.dv = 0 dp/ρ + g.dz + v.dv = 0 ρ.dp + g.dz + v.dv = 0 dp/ρ - g.dz + v.dv = 0 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A flow whose streamline is represented by a curve, is called Four-dimensional flow Two-dimensional flow One-dimensional flow Three-dimensional flow Four-dimensional flow Two-dimensional flow One-dimensional flow Three-dimensional flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The overall efficiency of a reaction turbine is the ratio of Power produced by the turbine to the energy actually supplied by the turbine None of these Work-done on the wheel to the energy (or head of water) actually supplied to the turbine Actual work available at the turbine to the energy imparted to the wheel Power produced by the turbine to the energy actually supplied by the turbine None of these Work-done on the wheel to the energy (or head of water) actually supplied to the turbine Actual work available at the turbine to the energy imparted to the wheel ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A differential manometer is used to measure Pressure in Venturimeter Pressure in pipes and channels Difference of pressures between two points in a pipe Atmospheric pressure Pressure in Venturimeter Pressure in pipes and channels Difference of pressures between two points in a pipe Atmospheric pressure ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × √H₂/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP
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