Hydraulics and Fluid Mechanics in ME The coefficient of discharge for an external mouthpiece depends upon Area of mouthpiece Pressure of liquid Velocity of liquid Length of mouthpiece Area of mouthpiece Pressure of liquid Velocity of liquid Length of mouthpiece ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The maximum hydraulic efficiency of an impulse turbine is (where φ = Angle of blade tip at outlet) (1 - cos φ)/2 (1 - sin φ)/2 (1 + cos φ)/2 (1 + sin φ)/2 (1 - cos φ)/2 (1 - sin φ)/2 (1 + cos φ)/2 (1 + sin φ)/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME For a perfect incompressible liquid, flowing in a continuous stream, the total energy of a particle remains the same, while the particle moves from one point to another. This statement is called Bernoulli’s equation Pascal’s law Archimedes’s principle Continuity equation Bernoulli’s equation Pascal’s law Archimedes’s principle Continuity equation ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME When the Venturimeter is inclined, then for a given flow it will show __________ reading. Less Same More None of these Less Same More None of these ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In open channels, the specific energy is the Total energy measured with respect to the datum passing through the bottom of the channel Kinetic energy plotted above the free surface of water Total energy per unit discharge Total energy measured above the horizontal datum Total energy measured with respect to the datum passing through the bottom of the channel Kinetic energy plotted above the free surface of water Total energy per unit discharge Total energy measured above the horizontal datum ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × √H₂/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP
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