Hydraulics and Fluid Mechanics in ME The force exerted by a moving fluid on an immersed body is directly proportional to the rate of change of momentum due to the presence of the body. This statement is called Newton's law of viscosity Newton's law of resistance Newton's law of motion Newton's law of cooling Newton's law of viscosity Newton's law of resistance Newton's law of motion Newton's law of cooling ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The depth of centre of pressure (h) for a vertically immersed surface from the liquid surface is given by (where IG = Moment of inertia of the immersed surface about horizontal axis through its centre of gravity, A = Area of immersed surface, and x = Depth of centre of gravity of the immersed surface from the liquid surface) (IG/Ax̅) + x̅ (IG/x̅) - Ax̅ (Ax̅/IG) + x̅ (IG/Ax̅) - x̅ (IG/Ax̅) + x̅ (IG/x̅) - Ax̅ (Ax̅/IG) + x̅ (IG/Ax̅) - x̅ ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In order to avoid cavitation in centrifugal pumps The delivery pressure should be low The suction pressure should be high The suction pressure should be low The delivery pressure should be high The delivery pressure should be low The suction pressure should be high The suction pressure should be low The delivery pressure should be high ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME If a pump is handling water and is discharging a certain flow Q at a constant total dynamic head requiring a definite B.H.P., the same pump when handling a liquid of specific gravity 0.75 and viscosity nearly same as of water , the horse power required will be 1.5 B.H.P Same H.P./0.75 0.75 B.H.P 1.5 B.H.P Same H.P./0.75 0.75 B.H.P ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The horizontal component of buoyant force is Same as buoyant force Negligible None of these Zero Same as buoyant force Negligible None of these Zero ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Bazin's formula, the discharge over a rectangular weir is mL2g x H3/2 where m is equal to 0.003 + (H/0.405) 0.003 + (0.405/H) 0.405 + (H/0.003) 0.405 + (0.003/H) 0.003 + (H/0.405) 0.003 + (0.405/H) 0.405 + (H/0.003) 0.405 + (0.003/H) ANSWER DOWNLOAD EXAMIANS APP
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