Hydraulics and Fluid Mechanics in ME For small discharge at high pressure, following pump is preferred Reciprocating Centrifugal Axial flow Mixed flow Reciprocating Centrifugal Axial flow Mixed flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Slip of a reciprocating pump is defined as the Ratio of actual discharge to the theoretical discharge Difference of theoretical discharge and the actual discharge Sum of actual discharge and the theoretical discharge Product of theoretical discharge and the actual discharge Ratio of actual discharge to the theoretical discharge Difference of theoretical discharge and the actual discharge Sum of actual discharge and the theoretical discharge Product of theoretical discharge and the actual discharge ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Density of water is maximum at 0°C 0°K 100°C 4°C 0°C 0°K 100°C 4°C ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The viscosity of a gas increases with increase in temperature is independent of pressure for very high pressure intensities is independent of temperature decreases with increase in temperature increases with increase in temperature is independent of pressure for very high pressure intensities is independent of temperature decreases with increase in temperature ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions) (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A hemispherical tank of radius (R) has an orifice of cross-sectional area (a) at its bottom and is full of liquid. The time required to empty the tank completely is 14π R3/2/15Cd × a √(2g) 14π R1/2/15Cd × a √(2g) 14π R5/2/15Cd × a √(2g) 14π R7/2/15Cd × a √(2g) 14π R3/2/15Cd × a √(2g) 14π R1/2/15Cd × a √(2g) 14π R5/2/15Cd × a √(2g) 14π R7/2/15Cd × a √(2g) ANSWER DOWNLOAD EXAMIANS APP
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