Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to empty the tank completely will be (2AH₁²)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) (2AH₁3/2)/(Cd × a√2g) (2AH₁²)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) (2AH₁3/2)/(Cd × a√2g) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The length AB of a pipe ABC in which the liquid is flowing has diameter (d1) and is suddenly contracted to diameter (d2) at B which is constant for the length BC. The loss of head due to sudden contraction, assuming coefficient of contraction as 0.62, is 0.375 v₂²/2g 0.5 v₁²/2g v₂²/2g v₁²/2g 0.375 v₂²/2g 0.5 v₁²/2g v₂²/2g v₁²/2g ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME When the velocity distribution is uniform over the cross-section, the correction factor for momentum is 2 1 43924 2 1 43924 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Which of the following is an example of laminar flow? Flow past tiny bodies All of these Flow of oil in measuring instruments Underground flow Flow past tiny bodies All of these Flow of oil in measuring instruments Underground flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The torque required to overcome viscous resistance of a footstep bearing is (where μ = Viscosity of the oil, N = Speed of the shaft, R = Radius of the shaft, and t = Thickness of the oil film) μπ²NR²/60t μπ²NR⁴/60t μπ²NR³/60t μπ²NR/60t μπ²NR²/60t μπ²NR⁴/60t μπ²NR³/60t μπ²NR/60t ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The variation in the volume of a liquid with the variation of pressure is called its Compressibility Viscosity Surface tension Capillarity Compressibility Viscosity Surface tension Capillarity ANSWER DOWNLOAD EXAMIANS APP
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