Estimating and Costing For 100 sq. m cement concrete (1 : 2: 4) 4 cm thick floor, the quantity of cement required, is 0.94 m³ 0.98 m³ 1.00 m³ 0.90 m³ 0.94 m³ 0.98 m³ 1.00 m³ 0.90 m³ ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The measurement is made for stone work in square metre in case of Wall facing Building work Columns, lintels, copings (A) and (B) of the above Wall facing Building work Columns, lintels, copings (A) and (B) of the above ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing In the mid-section formula The area of mid-sections is calculated by using mean depth The volume of the earth work is calculated by multiplying the mid-section area by the distance between the two original sections All of these The mean depth is the average of depths of two consecutive sections The area of mid-sections is calculated by using mean depth The volume of the earth work is calculated by multiplying the mid-section area by the distance between the two original sections All of these The mean depth is the average of depths of two consecutive sections ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The 'centre line method' is specially adopted for estimating All of these Octagonal buildings Circular buildings Hexagonal buildings All of these Octagonal buildings Circular buildings Hexagonal buildings ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The correct Prismoidal formula for volume is D [first area + last area + Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 4 Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 2 Ʃ Even area + 4 Ʃ odd areas] D/6 [first area + last area + 2 ∑ Even area + 4 ∑ odd areas] D [first area + last area + Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 4 Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 2 Ʃ Even area + 4 Ʃ odd areas] D/6 [first area + last area + 2 ∑ Even area + 4 ∑ odd areas] ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The cross-section of a road partly in banking and partly in cutting is shown in the given figure. The area of the shaded portion is ⅓ × (b - rd)²/(r + s) ⅓ × (b - rd)²/(r - s) ⅓ × (b - rd)²/(s - r) ½ × (b + rd)²/(r - s) ⅓ × (b - rd)²/(r + s) ⅓ × (b - rd)²/(r - s) ⅓ × (b - rd)²/(s - r) ½ × (b + rd)²/(r - s) ANSWER DOWNLOAD EXAMIANS APP
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