Estimating and Costing For 100 sq. m cement concrete (1 : 2: 4) 4 cm thick floor, the quantity of cement required, is 1.00 m³ 0.94 m³ 0.90 m³ 0.98 m³ 1.00 m³ 0.94 m³ 0.90 m³ 0.98 m³ ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The correct Prismoidal formula for volume is D [first area + last area + Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 4 Ʃ Even area + 2 Ʃ odd areas] D/6 [first area + last area + 2 ∑ Even area + 4 ∑ odd areas] D/3 [first area + last area + 2 Ʃ Even area + 4 Ʃ odd areas] D [first area + last area + Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 4 Ʃ Even area + 2 Ʃ odd areas] D/6 [first area + last area + 2 ∑ Even area + 4 ∑ odd areas] D/3 [first area + last area + 2 Ʃ Even area + 4 Ʃ odd areas] ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The ground surface slopes 1 in 50 along a proposed railway embankment 150 m in length. The height of the embankment at zero chainage is 0.5 m, the width is 11 m and side slopes 2:1. If the falling gradient of the embankment is 1 in 150, the quantity of the earthwork calculated by Prismoidal formula, is 3250 m³ 3225 m³ 3275 m³ 3300 m³ 3250 m³ 3225 m³ 3275 m³ 3300 m³ ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The trap which is provided to disconnect the house drain from the street sewer is called Master trap All listed here Intercepting trap Interception manhole Master trap All listed here Intercepting trap Interception manhole ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The area of a sloping surface of a protective embankment of mean height‘d’, side slopes S: 1 and length ‘L’ is √[d² × (ds)²] 2 L.D √(1 + s²) d × d × s L.D √(1 + s²) √[d² × (ds)²] 2 L.D √(1 + s²) d × d × s L.D √(1 + s²) ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing A cement concrete road is 1000 m long, 8 m wide and 15 cm thick over the sub-base of 10 cm thick gravel. The box cutting in road crust is 2000 m3 500 m3 1000 m3 1500 m3 2000 m3 500 m3 1000 m3 1500 m3 ANSWER DOWNLOAD EXAMIANS APP
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