Estimating and Costing For 100 sq. m cement concrete (1 : 2: 4) 4 cm thick floor, the quantity of cement required, is 0.90 m³ 0.94 m³ 0.98 m³ 1.00 m³ 0.90 m³ 0.94 m³ 0.98 m³ 1.00 m³ ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing Brick walls are measured in sq. m if the thickness of the wall is 10 cm 15 cm None of these 20 cm 10 cm 15 cm None of these 20 cm ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The ground surface slopes 1 in 50 along a proposed railway embankment 150 m in length. The height of the embankment at zero chainage is 0.5 m, the width is 11 m and side slopes 2:1. If the falling gradient of the embankment is 1 in 150, the quantity of the earthwork calculated by Prismoidal formula, is 3225 m³ 3250 m³ 3300 m³ 3275 m³ 3225 m³ 3250 m³ 3300 m³ 3275 m³ ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing Referring of given figure, pick up the correct statement from the following: Length of short walls in-to-in is 3.20 m The total length of centre line of four walls is 20 m Length of long wall out-to-out is 6.80 m All listed here Length of short walls in-to-in is 3.20 m The total length of centre line of four walls is 20 m Length of long wall out-to-out is 6.80 m All listed here ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing Pick up the correct statement regarding the centre line method of estimating a building The centre line is worked out separately for different sections of walls of a building The centre line length is reduced by half the layer of main wall joining the partition wall Product of the centre line of the walls and area of cross-section of any item, gives total quantity of the item All of these The centre line is worked out separately for different sections of walls of a building The centre line length is reduced by half the layer of main wall joining the partition wall Product of the centre line of the walls and area of cross-section of any item, gives total quantity of the item All of these ANSWER DOWNLOAD EXAMIANS APP
Estimating and Costing The correct Prismoidal formula for volume is D/3 [first area + last area + 2 Ʃ Even area + 4 Ʃ odd areas] D/6 [first area + last area + 2 ∑ Even area + 4 ∑ odd areas] D [first area + last area + Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 4 Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 2 Ʃ Even area + 4 Ʃ odd areas] D/6 [first area + last area + 2 ∑ Even area + 4 ∑ odd areas] D [first area + last area + Ʃ Even area + 2 Ʃ odd areas] D/3 [first area + last area + 4 Ʃ Even area + 2 Ʃ odd areas] ANSWER DOWNLOAD EXAMIANS APP
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