Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

It will fail to compile.
Compiles and runs printing
Compiles and runs with no output.
Runtime error

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int...args){}
static void add(int... args, int y){}
void add(Integer... args){}
static void add(int[]... args){}
static void add(int args...){}

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Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

IllegalArgumentException is thrown at runtime.
Compilation error.
InsideDemo 10 Hello2 hello1
InsideDemo 10 Hello2
Hello2 InsideDemo 10

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Declaration and Access Control
Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}}

r1 r4 pre b1 b2 post
r1 r4 pre b1 b2 post r3 r2
pre r1 r4 b1 b2 r2 r3 post
r1 r4 pre b1 b2 r3 r2 post
Compilation fail

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The program will lead to runtime error.
The program will lead to compilation error.
None of these
The will compile successfully and display 9 as output.
The program will compile successfully and display 10 as output.

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