Declaration and Access Control A package is a collection of Editing tools Classes Editing tools and Interfaces Classes and Interfaces Interfaces Editing tools Classes Editing tools and Interfaces Classes and Interfaces Interfaces ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;} None of these Any class. Any class in com.mypackage package. Any class that extends Test. Only the Test class. None of these Any class. Any class in com.mypackage package. Any class that extends Test. Only the Test class. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 1 and 3 1 and 2 3 and 4 2 and 4 1 and 3 1 and 2 3 and 4 2 and 4 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} Compile time error. one two 10 None of these one two 1 one two 0 Compile time error. one two 10 None of these one two 1 one two 0 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation clean but no output xyz Compilation fails abc None of these Compilation clean but no output xyz Compilation fails abc None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. Compilation error. InsideDemo 10 Hello2 Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. Compilation error. InsideDemo 10 Hello2 ANSWER DOWNLOAD EXAMIANS APP
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