Declaration and Access Control What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;} None of these Any class. Any class in com.mypackage package. Any class that extends Test. Only the Test class. None of these Any class. Any class in com.mypackage package. Any class that extends Test. Only the Test class. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 0 5 Runtime Exception 6 Compile with error 0 5 Runtime Exception 6 Compile with error ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int...args){} static void add(int args...){} void add(Integer... args){} static void add(int... args, int y){} static void add(int[]... args){} static void add(int...args){} static void add(int args...){} void add(Integer... args){} static void add(int... args, int y){} static void add(int[]... args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} Compilation Error Derived Exception is thrown at runtime BaseDerived Compilation Error Derived Exception is thrown at runtime BaseDerived ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. ANSWER DOWNLOAD EXAMIANS APP
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