Declaration and Access Control What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;} Any class in com.mypackage package. Only the Test class. None of these Any class. Any class that extends Test. Any class in com.mypackage package. Only the Test class. None of these Any class. Any class that extends Test. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control A package is a collection of Interfaces Classes Editing tools and Interfaces Editing tools Classes and Interfaces Interfaces Classes Editing tools and Interfaces Editing tools Classes and Interfaces ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} Compile time error. one two 1 None of these one two 0 one two 10 Compile time error. one two 1 None of these one two 0 one two 10 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. final abstract native volatile static final abstract native volatile static ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 Compilation error. IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 Compilation error. IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The will compile successfully and display 9 as output. The program will lead to runtime error. None of these The program will lead to compilation error. The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. The program will lead to runtime error. None of these The program will lead to compilation error. The program will compile successfully and display 10 as output. ANSWER DOWNLOAD EXAMIANS APP
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