Declaration and Access Control What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;} Any class. Any class that extends Test. Any class in com.mypackage package. Only the Test class. None of these Any class. Any class that extends Test. Any class in com.mypackage package. Only the Test class. None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int[]... args){} void add(Integer... args){} static void add(int...args){} static void add(int args...){} static void add(int... args, int y){} static void add(int[]... args){} void add(Integer... args){} static void add(int...args){} static void add(int args...){} static void add(int... args, int y){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword Depends on the code At run-time At Compile-time None of these Depends on the code At run-time At Compile-time None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} A block static static A None of these A static block A A block static static A None of these A static block A ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} one two 10 Compile time error. one two 0 None of these one two 1 one two 10 Compile time error. one two 0 None of these one two 1 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. ANSWER DOWNLOAD EXAMIANS APP
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