Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

Runtime Exception
0
Compile with error
6
5

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

None of these
The program will lead to compilation error.
The program will compile successfully and display 10 as output.
The program will lead to runtime error.
The will compile successfully and display 9 as output.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int[]... args){}
static void add(int...args){}
static void add(int args...){}
void add(Integer... args){}
static void add(int... args, int y){}

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