Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 6 5 Compile with error Runtime Exception 0 6 5 Compile with error Runtime Exception 0 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} BaseDerived Derived Compilation Error Exception is thrown at runtime BaseDerived Derived Compilation Error Exception is thrown at runtime ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int...args){} void add(Integer... args){} static void add(int[]... args){} static void add(int... args, int y){} static void add(int args...){} static void add(int...args){} void add(Integer... args){} static void add(int[]... args){} static void add(int... args, int y){} static void add(int args...){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} None of these The program will lead to compilation error. The program will lead to runtime error. The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. None of these The program will lead to compilation error. The program will lead to runtime error. The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program does not compile because Circle does not have a default constructor. The program has a compilation error because we cannot assign radius to radius. The program has a compilation error because it does not have a main method. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program does not compile because Circle does not have a default constructor. The program has a compilation error because we cannot assign radius to radius. The program has a compilation error because it does not have a main method. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} static A None of these A A block static static block A static A None of these A A block static static block A ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS