Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

6
Compile with error
5
0
Runtime Exception

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Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}}

Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 2 (constructors can't be static)
Compile error at line 3 (static methods can't invoke this)
Compile error at line 4 (invalid argument type for method main )
44

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Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}}

Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 2 (must access x by writing Tester.x)
Compile error at line 4 (invalid argument type for method main)
Compile error at line 3 (static methods can't make reference to non-static variables)
49

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

None of these
The program will compile successfully and display 10 as output.
The program will lead to compilation error.
The will compile successfully and display 9 as output.
The program will lead to runtime error.

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