Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 6 Compile with error 5 Runtime Exception 0 6 Compile with error 5 Runtime Exception 0 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will lead to compilation error. None of these The program will lead to runtime error. The will compile successfully and display 9 as output. The program will compile successfully and display 10 as output. The program will lead to compilation error. None of these The program will lead to runtime error. The will compile successfully and display 9 as output. The program will compile successfully and display 10 as output. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} 49 Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 4 (invalid argument type for method main) 49 Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 4 (invalid argument type for method main) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program has a compilation error because we cannot assign radius to radius. The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation clean but no output abc xyz Compilation fails None of these Compilation clean but no output abc xyz Compilation fails None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Compiles and runs printing Runtime error It will fail to compile. Compiles and runs with no output. Compiles and runs printing Runtime error It will fail to compile. Compiles and runs with no output. ANSWER DOWNLOAD EXAMIANS APP
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