Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 5 0 Runtime Exception Compile with error 6 5 0 Runtime Exception Compile with error 6 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} Exception is thrown at runtime Derived BaseDerived Compilation Error Exception is thrown at runtime Derived BaseDerived Compilation Error ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program has a compilation error because we cannot assign radius to radius. The program has a compilation error because it does not have a main method. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program does not compile because Circle does not have a default constructor. The program has a compilation error because we cannot assign radius to radius. The program has a compilation error because it does not have a main method. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program does not compile because Circle does not have a default constructor. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int... args, int y){} static void add(int args...){} void add(Integer... args){} static void add(int...args){} static void add(int[]... args){} static void add(int... args, int y){} static void add(int args...){} void add(Integer... args){} static void add(int...args){} static void add(int[]... args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword At Compile-time Depends on the code At run-time None of these At Compile-time Depends on the code At run-time None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. ANSWER DOWNLOAD EXAMIANS APP
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