Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

Runtime Exception
Compile with error
0
5
6

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int... args, int y){}
static void add(int...args){}
void add(Integer... args){}
static void add(int args...){}
static void add(int[]... args){}

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

The program has a compilation error because we cannot assign radius to radius.
The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0.
The program does not compile because Circle does not have a default constructor.
The program has a compilation error because it does not have a main method.

ANSWER DOWNLOAD EXAMIANS APP