Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

0
5
6
Compile with error
Runtime Exception

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The program will compile successfully and display 10 as output.
None of these
The program will lead to runtime error.
The program will lead to compilation error.
The will compile successfully and display 9 as output.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int args...){}
void add(Integer... args){}
static void add(int[]... args){}
static void add(int... args, int y){}
static void add(int...args){}

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Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}}

Compile error at line 3 (static methods can't invoke this)
Compile error at line 2 (constructors can't be static)
Compile error at line 4 (invalid argument type for method main )
44
Compile error at line 1 (static x must be only accessed inside static methods)

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