Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

Runtime Exception
0
Compile with error
5
6

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Compilation error.
IllegalArgumentException is thrown at runtime.
InsideDemo 10 Hello2 hello1
Hello2 InsideDemo 10
InsideDemo 10 Hello2

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}}

Compile error at line 4 (invalid argument type for method main)
49
Compile error at line 3 (static methods can't make reference to non-static variables)
Compile error at line 2 (must access x by writing Tester.x)
Compile error at line 1 (static x must be only accessed inside static methods)

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

The program has a compilation error because we cannot assign radius to radius.
The program does not compile because Circle does not have a default constructor.
The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0.
The program has a compilation error because it does not have a main method.

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

one
Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.
Compile error - char can't be permitted in switch statement.
None of these
two

ANSWER DOWNLOAD EXAMIANS APP