Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}}

49
Compile error at line 3 (static methods can't make reference to non-static variables)
Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 4 (invalid argument type for method main)
Compile error at line 2 (must access x by writing Tester.x)

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

This method is only accessible from inside the class itself and from inside all subclasses.
From within protected methods you do not have access to public methods.
In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

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Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Compilation error.
Hello2 InsideDemo 10
InsideDemo 10 Hello2
IllegalArgumentException is thrown at runtime.
InsideDemo 10 Hello2 hello1

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The will compile successfully and display 9 as output.
The program will lead to runtime error.
The program will compile successfully and display 10 as output.
None of these
The program will lead to compilation error.

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