Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}}

49
Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 3 (static methods can't make reference to non-static variables)
Compile error at line 4 (invalid argument type for method main)
Compile error at line 2 (must access x by writing Tester.x)

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Compilation error.
InsideDemo 10 Hello2
Hello2 InsideDemo 10
InsideDemo 10 Hello2 hello1
IllegalArgumentException is thrown at runtime.

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int[]... args){}
void add(Integer... args){}
static void add(int...args){}
static void add(int args...){}
static void add(int... args, int y){}

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Declaration and Access Control