Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

From within protected methods you do not have access to public methods.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.
This method is only accessible from inside the class itself and from inside all subclasses.
In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int args...){}
static void add(int... args, int y){}
static void add(int...args){}
void add(Integer... args){}
static void add(int[]... args){}

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

None of these
Compile error - char can't be permitted in switch statement.
Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.
two
one

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}}

Compile error at line 3 (static methods can't make reference to non-static variables)
Compile error at line 2 (must access x by writing Tester.x)
49
Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 4 (invalid argument type for method main)

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

InsideDemo 10 Hello2 hello1
InsideDemo 10 Hello2
Hello2 InsideDemo 10
Compilation error.
IllegalArgumentException is thrown at runtime.

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Declaration and Access Control