Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

From within protected methods you do not have access to public methods.

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

This method is only accessible from inside the class itself and from inside all subclasses.

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

From within protected methods you do not have access to public methods.

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

This method is only accessible from inside the class itself and from inside all subclasses.

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

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Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Compiles and runs printing

Runtime error

Compiles and runs with no output.

It will fail to compile.

Compiles and runs printing

Runtime error

Compiles and runs with no output.

It will fail to compile.

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Declaration and Access Control
Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class.

final

abstract

volatile

static

native

final

abstract

volatile

static

native

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Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.

Compile error - char can't be permitted in switch statement.

None of these

two

one

Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.

Compile error - char can't be permitted in switch statement.

None of these

two

one

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Declaration and Access Control
What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

None of these

static block A

static A

A

A block static

None of these

static block A

static A

A

A block static

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Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Exception is thrown at runtime

Derived

BaseDerived

Compilation Error

Exception is thrown at runtime

Derived

BaseDerived

Compilation Error

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Declaration and Access Control

Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class.

Declaration and Access Control What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Declaration and Access Control
Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class.

Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

Declaration and Access Control
What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}