What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

BaseDerived

Derived

Exception is thrown at runtime

Compilation Error

BaseDerived

Derived

Exception is thrown at runtime

Compilation Error

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Declaration and Access Control
What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }}

None of these

Compilation clean but no output

xyz

Compilation fails

abc

None of these

Compilation clean but no output

xyz

Compilation fails

abc

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Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

IllegalArgumentException is thrown at runtime.

Hello2 InsideDemo 10

InsideDemo 10 Hello2 hello1

InsideDemo 10 Hello2

Compilation error.

IllegalArgumentException is thrown at runtime.

Hello2 InsideDemo 10

InsideDemo 10 Hello2 hello1

InsideDemo 10 Hello2

Compilation error.

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Declaration and Access Control
Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class.

native

abstract

static

volatile

final

native

abstract

static

volatile

final

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int[]... args){}

static void add(int args...){}

static void add(int... args, int y){}

static void add(int...args){}

void add(Integer... args){}

static void add(int[]... args){}

static void add(int args...){}

static void add(int... args, int y){}

static void add(int...args){}

void add(Integer... args){}

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Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Compiles and runs with no output.

It will fail to compile.

Compiles and runs printing

Runtime error

Compiles and runs with no output.

It will fail to compile.

Compiles and runs printing

Runtime error

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Declaration and Access Control

Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }}

Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class.

Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Declaration and Access Control
What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }}

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Declaration and Access Control
Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class.

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?