Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Exception is thrown at runtime
Compilation Error
BaseDerived
Derived

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.
This method is only accessible from inside the class itself and from inside all subclasses.
From within protected methods you do not have access to public methods.

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

None of these
one
Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.
Compile error - char can't be permitted in switch statement.
two

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Declaration and Access Control