Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Compilation Error
BaseDerived
Exception is thrown at runtime
Derived

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A();

1 and 3
3 and 4
1 and 2
2 and 4

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Hello2 InsideDemo 10
InsideDemo 10 Hello2 hello1
Compilation error.
IllegalArgumentException is thrown at runtime.
InsideDemo 10 Hello2

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

void add(Integer... args){}
static void add(int args...){}
static void add(int... args, int y){}
static void add(int...args){}
static void add(int[]... args){}

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Declaration and Access Control