Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

InsideDemo 10 Hello2 hello1
Compilation error.
IllegalArgumentException is thrown at runtime.
Hello2 InsideDemo 10
InsideDemo 10 Hello2

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

None of these
The program will lead to runtime error.
The program will compile successfully and display 10 as output.
The program will lead to compilation error.
The will compile successfully and display 9 as output.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

void add(Integer... args){}
static void add(int[]... args){}
static void add(int args...){}
static void add(int...args){}
static void add(int... args, int y){}

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