Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

IllegalArgumentException is thrown at runtime.

Hello2 InsideDemo 10

InsideDemo 10 Hello2 hello1

Compilation error.

InsideDemo 10 Hello2

IllegalArgumentException is thrown at runtime.

Hello2 InsideDemo 10

InsideDemo 10 Hello2 hello1

Compilation error.

InsideDemo 10 Hello2

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Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

one two 1

None of these

one two 0

Compile time error.

one two 10

one two 1

None of these

one two 0

Compile time error.

one two 10

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int args...){}

void add(Integer... args){}

static void add(int...args){}

static void add(int[]... args){}

static void add(int... args, int y){}

static void add(int args...){}

void add(Integer... args){}

static void add(int...args){}

static void add(int[]... args){}

static void add(int... args, int y){}

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Declaration and Access Control
The object is created with new keyword

Depends on the code

None of these

At run-time

At Compile-time

Depends on the code

None of these

At run-time

At Compile-time

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Declaration and Access Control
What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

A block static

static block A

static A

A

None of these

A block static

static block A

static A

A

None of these

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Declaration and Access Control
What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }}

Runtime Exception

0

5

Compile with error

None of these

Runtime Exception

0

5

Compile with error

None of these

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Declaration and Access Control

Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

Declaration and Access Control The object is created with new keyword

Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }}

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

Declaration and Access Control
The object is created with new keyword

Declaration and Access Control
What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

Declaration and Access Control
What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }}