Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

IllegalArgumentException is thrown at runtime.
InsideDemo 10 Hello2
Compilation error.
InsideDemo 10 Hello2 hello1
Hello2 InsideDemo 10

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The will compile successfully and display 9 as output.
The program will lead to runtime error.
The program will compile successfully and display 10 as output.
None of these
The program will lead to compilation error.

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Declaration and Access Control
Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

The program does not compile because Circle does not have a default constructor.
The program has a compilation error because it does not have a main method.
The program has a compilation error because we cannot assign radius to radius.
The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

void add(Integer... args){}
static void add(int[]... args){}
static void add(int... args, int y){}
static void add(int args...){}
static void add(int...args){}

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

This method is only accessible from inside the class itself and from inside all subclasses.
In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.
From within protected methods you do not have access to public methods.

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