Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Hello2 InsideDemo 10
IllegalArgumentException is thrown at runtime.
InsideDemo 10 Hello2 hello1
InsideDemo 10 Hello2
Compilation error.

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Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}}

44
Compile error at line 3 (static methods can't invoke this)
Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 2 (constructors can't be static)
Compile error at line 4 (invalid argument type for method main )

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The will compile successfully and display 9 as output.
None of these
The program will lead to compilation error.
The program will compile successfully and display 10 as output.
The program will lead to runtime error.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int... args, int y){}
static void add(int args...){}
void add(Integer... args){}
static void add(int[]... args){}
static void add(int...args){}

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