Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} None of these 5 0 Runtime Exception Compile with error None of these 5 0 Runtime Exception Compile with error ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 5 0 Compile with error 6 Runtime Exception 5 0 Compile with error 6 Runtime Exception ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Compiles and runs with no output. It will fail to compile. Runtime error Compiles and runs printing Compiles and runs with no output. It will fail to compile. Runtime error Compiles and runs printing ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Compilation error. InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 Hello2 InsideDemo 10 IllegalArgumentException is thrown at runtime. Compilation error. InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 Hello2 InsideDemo 10 IllegalArgumentException is thrown at runtime. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} Compile time error. one two 10 None of these one two 1 one two 0 Compile time error. one two 10 None of these one two 1 one two 0 ANSWER DOWNLOAD EXAMIANS APP
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