Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} Compile with error Runtime Exception None of these 0 5 Compile with error Runtime Exception None of these 0 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} r1 r4 pre b1 b2 post r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post Compilation fail r1 r4 pre b1 b2 post r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post Compilation fail ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} None of these The program will lead to compilation error. The will compile successfully and display 9 as output. The program will compile successfully and display 10 as output. The program will lead to runtime error. None of these The program will lead to compilation error. The will compile successfully and display 9 as output. The program will compile successfully and display 10 as output. The program will lead to runtime error. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} Compile with error 6 0 Runtime Exception 5 Compile with error 6 0 Runtime Exception 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. native final static abstract volatile native final static abstract volatile ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} 49 Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 4 (invalid argument type for method main) Compile error at line 1 (static x must be only accessed inside static methods) 49 Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 4 (invalid argument type for method main) Compile error at line 1 (static x must be only accessed inside static methods) ANSWER DOWNLOAD EXAMIANS APP
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