Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} 5 0 None of these Compile with error Runtime Exception 5 0 None of these Compile with error Runtime Exception ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 Compilation error. IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 Compilation error. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is only accessible from inside the class itself and from inside all subclasses. From within protected methods you do not have access to public methods. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is only accessible from inside the class itself and from inside all subclasses. From within protected methods you do not have access to public methods. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} xyz None of these Compilation clean but no output Compilation fails abc xyz None of these Compilation clean but no output Compilation fails abc ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword Depends on the code At run-time At Compile-time None of these Depends on the code At run-time At Compile-time None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} A block static static block A static A A None of these A block static static block A static A A None of these ANSWER DOWNLOAD EXAMIANS APP
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