Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A();

Declaration and Access Control
Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A();

1 and 3

1 and 2

3 and 4

2 and 4

1 and 3

1 and 2

3 and 4

2 and 4

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}}

Compile error at line 1 (static x must be only accessed inside static methods)

Compile error at line 4 (invalid argument type for method main)

49

Compile error at line 3 (static methods can't make reference to non-static variables)

Compile error at line 2 (must access x by writing Tester.x)

Compile error at line 1 (static x must be only accessed inside static methods)

Compile error at line 4 (invalid argument type for method main)

49

Compile error at line 3 (static methods can't make reference to non-static variables)

Compile error at line 2 (must access x by writing Tester.x)

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

void add(Integer... args){}

static void add(int args...){}

static void add(int...args){}

static void add(int... args, int y){}

static void add(int[]... args){}

void add(Integer... args){}

static void add(int args...){}

static void add(int...args){}

static void add(int... args, int y){}

static void add(int[]... args){}

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Compiles and runs with no output.

Runtime error

It will fail to compile.

Compiles and runs printing

Compiles and runs with no output.

Runtime error

It will fail to compile.

Compiles and runs printing

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }}

None of these

xyz

Compilation fails

Compilation clean but no output

abc

None of these

xyz

Compilation fails

Compilation clean but no output

abc

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

Compile with error

6

5

Runtime Exception

0

Compile with error

6

5

Runtime Exception

0

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control

Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }}

Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Declaration and Access Control
What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }}

Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}