Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

one two 0
one two 1
one two 10
None of these
Compile time error.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int[]... args){}
void add(Integer... args){}
static void add(int... args, int y){}
static void add(int args...){}
static void add(int...args){}

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Declaration and Access Control
Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

The program does not compile because Circle does not have a default constructor.
The program has a compilation error because it does not have a main method.
The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0.
The program has a compilation error because we cannot assign radius to radius.

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

This method is only accessible from inside the class itself and from inside all subclasses.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.
From within protected methods you do not have access to public methods.
In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

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