Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

one two 1
Compile time error.
None of these
one two 0
one two 10

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Declaration and Access Control
Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}}

r1 r4 pre b1 b2 post
pre r1 r4 b1 b2 r2 r3 post
r1 r4 pre b1 b2 r3 r2 post
r1 r4 pre b1 b2 post r3 r2
Compilation fail

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

From within protected methods you do not have access to public methods.
This method is only accessible from inside the class itself and from inside all subclasses.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.
In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

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Declaration and Access Control
A method within a class is only accessible by classes that are defined within the same package as the class of the method. Which one of the following is used to enforce such restriction?

Declare the method with the keyword public.
Declare the method with the keyword protected.
Declare the method with the keyword public and private.
Declare the method with the keyword private.
Do not declare the method with any accessibility modifiers.

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The program will lead to compilation error.
The program will compile successfully and display 10 as output.
The program will lead to runtime error.
The will compile successfully and display 9 as output.
None of these

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