Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. final volatile native abstract static final volatile native abstract static ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} one 20 one two 20 20 one two one one 20 one two 20 20 one two one ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 4 (invalid argument type for method main) 49 Compile error at line 2 (must access x by writing Tester.x) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 4 (invalid argument type for method main) 49 Compile error at line 2 (must access x by writing Tester.x) Compile error at line 1 (static x must be only accessed inside static methods) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Compiles and runs with no output. Runtime error It will fail to compile. Compiles and runs printing Compiles and runs with no output. Runtime error It will fail to compile. Compiles and runs printing ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int... args, int y){} static void add(int args...){} static void add(int[]... args){} static void add(int...args){} void add(Integer... args){} static void add(int... args, int y){} static void add(int args...){} static void add(int[]... args){} static void add(int...args){} void add(Integer... args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 1 and 3 2 and 4 3 and 4 1 and 2 1 and 3 2 and 4 3 and 4 1 and 2 ANSWER DOWNLOAD EXAMIANS APP
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