Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. final static native volatile abstract final static native volatile abstract ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main) Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 2 (must access x by writing Tester.x) 49 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main) Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 2 (must access x by writing Tester.x) 49 Compile error at line 1 (static x must be only accessed inside static methods) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword At Compile-time At run-time Depends on the code None of these At Compile-time At run-time Depends on the code None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} r1 r4 pre b1 b2 post r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post Compilation fail r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post Compilation fail r1 r4 pre b1 b2 r3 r2 post ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} one two 20 20 one 20 one one two one two 20 20 one 20 one one two ANSWER DOWNLOAD EXAMIANS APP
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