Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

void add(Integer... args){}
static void add(int... args, int y){}
static void add(int[]... args){}
static void add(int args...){}
static void add(int...args){}

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Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}}

Compile error at line 4 (invalid argument type for method main)
49
Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 2 (must access x by writing Tester.x)
Compile error at line 3 (static methods can't make reference to non-static variables)

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The program will lead to compilation error.
None of these
The program will compile successfully and display 10 as output.
The program will lead to runtime error.
The will compile successfully and display 9 as output.

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Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

Compilation error.
InsideDemo 10 Hello2 hello1
InsideDemo 10 Hello2
Hello2 InsideDemo 10
IllegalArgumentException is thrown at runtime.

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