Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 post r3 r2 r1 r4 pre b1 b2 r3 r2 post Compilation fail r1 r4 pre b1 b2 post pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 post r3 r2 r1 r4 pre b1 b2 r3 r2 post Compilation fail r1 r4 pre b1 b2 post ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these Compilation clean but no output Compilation fails abc xyz None of these Compilation clean but no output Compilation fails abc xyz ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword Depends on the code At run-time At Compile-time None of these Depends on the code At run-time At Compile-time None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} void add(Integer... args){} static void add(int[]... args){} static void add(int... args, int y){} static void add(int args...){} static void add(int...args){} void add(Integer... args){} static void add(int[]... args){} static void add(int... args, int y){} static void add(int args...){} static void add(int...args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} 20 one two 20 one two one 20 one 20 one two 20 one two one 20 one ANSWER DOWNLOAD EXAMIANS APP
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