Declaration and Access Control Choose the correct statement. Restriction on static methods are: I. They can only call other static methods.II. They must only access static data.III. They cannot refer this or super in any way. (II) and (III) (I), (II) and (III) (I) and (II) Only (I) Only (III) (II) and (III) (I), (II) and (III) (I) and (II) Only (I) Only (III) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 3 and 4 1 and 2 2 and 4 1 and 3 3 and 4 1 and 2 2 and 4 1 and 3 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}} 44 Compile error at line 3 (static methods can't invoke this) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) 44 Compile error at line 3 (static methods can't invoke this) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int[]... args){} static void add(int...args){} void add(Integer... args){} static void add(int args...){} static void add(int... args, int y){} static void add(int[]... args){} static void add(int...args){} void add(Integer... args){} static void add(int args...){} static void add(int... args, int y){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will lead to runtime error. The program will lead to compilation error. The program will compile successfully and display 10 as output. None of these The will compile successfully and display 9 as output. The program will lead to runtime error. The program will lead to compilation error. The program will compile successfully and display 10 as output. None of these The will compile successfully and display 9 as output. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 post r1 r4 pre b1 b2 r3 r2 post Compilation fail r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 post r1 r4 pre b1 b2 r3 r2 post Compilation fail r1 r4 pre b1 b2 post r3 r2 ANSWER DOWNLOAD EXAMIANS APP
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