Declaration and Access Control Choose the correct statement. Restriction on static methods are: I. They can only call other static methods.II. They must only access static data.III. They cannot refer this or super in any way. Only (III) (I), (II) and (III) Only (I) (II) and (III) (I) and (II) Only (III) (I), (II) and (III) Only (I) (II) and (III) (I) and (II) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int...args){} static void add(int... args, int y){} static void add(int args...){} static void add(int[]... args){} void add(Integer... args){} static void add(int...args){} static void add(int... args, int y){} static void add(int args...){} static void add(int[]... args){} void add(Integer... args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 3 and 4 1 and 2 2 and 4 1 and 3 3 and 4 1 and 2 2 and 4 1 and 3 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} abc Compilation fails None of these xyz Compilation clean but no output abc Compilation fails None of these xyz Compilation clean but no output ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 0 5 Compile with error Runtime Exception 6 0 5 Compile with error Runtime Exception 6 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} static block A A static A None of these A block static static block A A static A None of these A block static ANSWER DOWNLOAD EXAMIANS APP
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