Declaration and Access Control The object is created with new keyword At run-time At Compile-time None of these Depends on the code At run-time At Compile-time None of these Depends on the code ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. static volatile final native abstract static volatile final native abstract ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} void add(Integer... args){} static void add(int...args){} static void add(int args...){} static void add(int[]... args){} static void add(int... args, int y){} void add(Integer... args){} static void add(int...args){} static void add(int args...){} static void add(int[]... args){} static void add(int... args, int y){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 5 6 Runtime Exception Compile with error 0 5 6 Runtime Exception Compile with error 0 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Compiles and runs printing Runtime error It will fail to compile. Compiles and runs with no output. Compiles and runs printing Runtime error It will fail to compile. Compiles and runs with no output. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} one two 0 one two 1 None of these Compile time error. one two 10 one two 0 one two 1 None of these Compile time error. one two 10 ANSWER DOWNLOAD EXAMIANS APP
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