Declaration and Access Control The object is created with new keyword At Compile-time At run-time None of these Depends on the code At Compile-time At run-time None of these Depends on the code ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 IllegalArgumentException is thrown at runtime. Compilation error. Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 IllegalArgumentException is thrown at runtime. Compilation error. Hello2 InsideDemo 10 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int...args){} static void add(int args...){} static void add(int... args, int y){} void add(Integer... args){} static void add(int[]... args){} static void add(int...args){} static void add(int args...){} static void add(int... args, int y){} void add(Integer... args){} static void add(int[]... args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. abstract native final static volatile abstract native final static volatile ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} None of these Compile time error. one two 10 one two 0 one two 1 None of these Compile time error. one two 10 one two 0 one two 1 ANSWER DOWNLOAD EXAMIANS APP
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