Declaration and Access Control The object is created with new keyword None of these Depends on the code At run-time At Compile-time None of these Depends on the code At run-time At Compile-time ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Hello2 InsideDemo 10 Compilation error. InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 Compilation error. InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 IllegalArgumentException is thrown at runtime. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} 20 one two one 20 one two 20 one 20 one two one 20 one two 20 one ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int[]... args){} static void add(int args...){} static void add(int...args){} void add(Integer... args){} static void add(int... args, int y){} static void add(int[]... args){} static void add(int args...){} static void add(int...args){} void add(Integer... args){} static void add(int... args, int y){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} xyz Compilation clean but no output abc None of these Compilation fails xyz Compilation clean but no output abc None of these Compilation fails ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. ANSWER DOWNLOAD EXAMIANS APP
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