Declaration and Access Control The object is created with new keyword At run-time At Compile-time Depends on the code None of these At run-time At Compile-time Depends on the code None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control A method within a class is only accessible by classes that are defined within the same package as the class of the method. Which one of the following is used to enforce such restriction? Declare the method with the keyword protected. Declare the method with the keyword private. Declare the method with the keyword public. Declare the method with the keyword public and private. Do not declare the method with any accessibility modifiers. Declare the method with the keyword protected. Declare the method with the keyword private. Declare the method with the keyword public. Declare the method with the keyword public and private. Do not declare the method with any accessibility modifiers. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 4 (invalid argument type for method main) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 2 (must access x by writing Tester.x) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} one one two 20 one 20 20 one two one one two 20 one 20 20 one two ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post Compilation fail r1 r4 pre b1 b2 post r3 r2 pre r1 r4 b1 b2 r2 r3 post r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post Compilation fail ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program does not compile because Circle does not have a default constructor. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program does not compile because Circle does not have a default constructor. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. ANSWER DOWNLOAD EXAMIANS APP
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