Declaration and Access Control The object is created with new keyword At Compile-time Depends on the code None of these At run-time At Compile-time Depends on the code None of these At run-time ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} None of these one two 1 Compile time error. one two 10 one two 0 None of these one two 1 Compile time error. one two 10 one two 0 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) 49 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) 49 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't make reference to non-static variables) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 Compilation error. Hello2 InsideDemo 10 InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 Compilation error. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} xyz abc Compilation fails Compilation clean but no output None of these xyz abc Compilation fails Compilation clean but no output None of these ANSWER DOWNLOAD EXAMIANS APP
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