Declaration and Access Control The object is created with new keyword At run-time At Compile-time None of these Depends on the code At run-time At Compile-time None of these Depends on the code ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Runtime error Compiles and runs with no output. It will fail to compile. Compiles and runs printing Runtime error Compiles and runs with no output. It will fail to compile. Compiles and runs printing ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} static block A A block static static A None of these A static block A A block static static A None of these A ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control A method within a class is only accessible by classes that are defined within the same package as the class of the method. Which one of the following is used to enforce such restriction? Declare the method with the keyword protected. Declare the method with the keyword public. Do not declare the method with any accessibility modifiers. Declare the method with the keyword private. Declare the method with the keyword public and private. Declare the method with the keyword protected. Declare the method with the keyword public. Do not declare the method with any accessibility modifiers. Declare the method with the keyword private. Declare the method with the keyword public and private. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}} Compile error at line 3 (static methods can't invoke this) 44 Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't invoke this) 44 Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) Compile error at line 1 (static x must be only accessed inside static methods) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is only accessible from inside the class itself and from inside all subclasses. From within protected methods you do not have access to public methods. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is only accessible from inside the class itself and from inside all subclasses. From within protected methods you do not have access to public methods. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. ANSWER DOWNLOAD EXAMIANS APP
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