Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

None of these
The will compile successfully and display 9 as output.
The program will lead to compilation error.
The program will lead to runtime error.
The program will compile successfully and display 10 as output.

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.
In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.
This method is only accessible from inside the class itself and from inside all subclasses.
From within protected methods you do not have access to public methods.

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Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

None of these
Compile error - char can't be permitted in switch statement.
one
Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.
two

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Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

InsideDemo 10 Hello2
InsideDemo 10 Hello2 hello1
Hello2 InsideDemo 10
Compilation error.
IllegalArgumentException is thrown at runtime.

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