Microprocessor Which language could be used for programming an FPGA. None VHDL Both A and B Verilog None VHDL Both A and B Verilog ANSWER DOWNLOAD EXAMIANS APP
Microprocessor Assertion(A): Segment override prefix (SOP) is used when a default offset register is not used with its default base segment register but with a different base register. Reason(R): The offset registers IP and SP can never be associated with any other segment registers apart from their respective default segments. A is true but R is false. A is false but R is true. Both A & R are true and R is the correct explanation of A. Both A & R are true but R is not the correct explanation of A. A is true but R is false. A is false but R is true. Both A & R are true and R is the correct explanation of A. Both A & R are true but R is not the correct explanation of A. ANSWER DOWNLOAD EXAMIANS APP
Microprocessor Which of the following is not true during the execution of an interrupt service routine, which does not contain any EI instructions the microprocessor can be interrupted by a non-mask able interrupt the microprocessor cannot be interrupted by any interrupt the microprocessor cannot be interrupted by any mask able interrupt all interrupts except non-maskable interrupt are disabled the microprocessor can be interrupted by a non-mask able interrupt the microprocessor cannot be interrupted by any interrupt the microprocessor cannot be interrupted by any mask able interrupt all interrupts except non-maskable interrupt are disabled ANSWER DOWNLOAD EXAMIANS APP
Microprocessor The reason for the presence of ALE pin in 8085, but not in 6800 is that 8085 has multiplexed bus, whereas 6800 does not have 8085 has 5 interrupts lines, whereas 6800 has only two None 8085 uses I/O mapped I/O, whereas 6800 uses memory mapped I/O 8085 has multiplexed bus, whereas 6800 does not have 8085 has 5 interrupts lines, whereas 6800 has only two None 8085 uses I/O mapped I/O, whereas 6800 uses memory mapped I/O ANSWER DOWNLOAD EXAMIANS APP
Microprocessor When .9432 E – 4 is subtracted from .5452 E – 3 in normalized floating point mode .9432 E – 4 is changed to .09432 E – 3 and .5452 E – 3 is not changed None of the numbers is changed Both Ihe numbers are changed and their exponents are, made equal to -5 .5452 E – 3 is changed to 5.452 E – 4 but .9432 E – 4 is not changed .9432 E – 4 is changed to .09432 E – 3 and .5452 E – 3 is not changed None of the numbers is changed Both Ihe numbers are changed and their exponents are, made equal to -5 .5452 E – 3 is changed to 5.452 E – 4 but .9432 E – 4 is not changed ANSWER DOWNLOAD EXAMIANS APP
Microprocessor If the number of address bits in a memory is reduced by 2 and the addressability is doubled, the size of the memory (i.e., the number of bits stored in the memory) Doubles Halves Increases by 2^(address bits)/addressability Remains unchanged Doubles Halves Increases by 2^(address bits)/addressability Remains unchanged ANSWER DOWNLOAD EXAMIANS APP
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