Theory of Machine When a point moves along a straight line, its acceleration will have Radial and tangential components both Radial component only Tangential component only Coriolis component only Radial and tangential components both Radial component only Tangential component only Coriolis component only ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the axes of the first and last wheels are coaxial, then the train is known as Compound train of wheels Epicyclic gear train Simple train of wheels Reverted gear train Compound train of wheels Epicyclic gear train Simple train of wheels Reverted gear train ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The primary unbalanced force is maximum _________ in one revolution of the crank. Eight times Sixteen times Four times Twice Eight times Sixteen times Four times Twice ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The two links OA and OB are connected by a pin joint at O. If the link OA turns with angular velocity ω₁ rad/s in the clockwise direction and the link OB turns with angular velocity ω₂ rad/s in the anticlockwise direction, then the rubbing velocity at the pin joint O is (where r = Radius of the pin at O) (ω₁ + ω₂) r (ω₁ - ω₂) 2r (ω₁ - ω₂) r ω₁.ω₂.r (ω₁ + ω₂) r (ω₁ - ω₂) 2r (ω₁ - ω₂) r ω₁.ω₂.r ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r (cos 2θ/n) m.ω².r cosθ m.ω².r (sin 2θ/n) m.ω².r sinθ m.ω².r (cos 2θ/n) m.ω².r cosθ m.ω².r (sin 2θ/n) m.ω².r sinθ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ ANSWER DOWNLOAD EXAMIANS APP
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