Process Equipment and Plant Design The main purpose of providing stepping on the trays is to Increase the residence time Improve the flow condition Decrease the pressure drop Facilitate handling of large flow rate of liquid Increase the residence time Improve the flow condition Decrease the pressure drop Facilitate handling of large flow rate of liquid ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design An increase in the liquid resistance to interphase mass transfer and a resultant reduction in plate efficiency is caused by Decrease in gas solubility for absorbers An increase in liquid viscosity An increase in relatived volatility for rectification columns All of these Decrease in gas solubility for absorbers An increase in liquid viscosity An increase in relatived volatility for rectification columns All of these ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Heat transfer co-efficient, hG(Kcal/hr.m² .°C) and mass velocity of air, G (kg/hr.m² ) for air flow parallel to the surface in case of constant drying rate in batch drying is related as hG = 0.0176G0.8. But when the flow of air perpendicular to the surface is encountered, this equation changes to 1.004G0.8 HG = 1.004G0.37 0.0176G1.37 HG = 0.0176G0.37 1.004G0.8 HG = 1.004G0.37 0.0176G1.37 HG = 0.0176G0.37 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The practical representative values of HETP for a number of commercial operations lies within a range of __________ metre. 0.1-0.2 0.4-0.9 1.2-1.5 0.2-0.5 0.1-0.2 0.4-0.9 1.2-1.5 0.2-0.5 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Bracket supports are the most suitable for supporting __________ vessels. Thin shperical (e.g. Horton sphere) Thick walled vertical None of these Horizontal Thin shperical (e.g. Horton sphere) Thick walled vertical None of these Horizontal ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design In a shell and tube heat exchanger having square pitch, the shell side equivalent diameter is given by (where, P = pitch, d = outside diameter of the tube) (P² - πd²/4)/πd 4(P² - πd²/4)/πd Πd/4P² 4P²/πd (P² - πd²/4)/πd 4(P² - πd²/4)/πd Πd/4P² 4P²/πd ANSWER DOWNLOAD EXAMIANS APP
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