Process Equipment and Plant Design The thickness of heat transfer plates used in the plate type heat exchanger ranges from __________ mm, pressed in a single piece provided with grooves & corrugations. 3.5 to 7.0 0.3 to 0.8 44055 1.25 to 3.125 3.5 to 7.0 0.3 to 0.8 44055 1.25 to 3.125 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For a cylindrical shell, (subject to the thickness of uppermost course being more than the minimum for diaofthe tank in question), the thickness of the courses of shell Decreases upwards Increases upwards May decrease or increase upwards depending upon whether vacuum or positive pressure would be maintained inside the shell Remains same throughout Decreases upwards Increases upwards May decrease or increase upwards depending upon whether vacuum or positive pressure would be maintained inside the shell Remains same throughout ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For a cylinderical internally pressurised vessel, which of the following closure types would withstand highest pressure, if each closure is of the same material and thickness? Hemispherical Ellipsoidal (2 : 1) Conical Flat plate Hemispherical Ellipsoidal (2 : 1) Conical Flat plate ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Joint efficiency (J) for a seamless pipe is 1 < 0.5 1.2 0.85 1 < 0.5 1.2 0.85 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design A forced circulation long tube vertical evaporator as compared to the natural circulation evaporator Is economical in operation Employs high velocity, high heat transfer rate and less heating surface requirement Employs a centrifugal pump placed between external downtake from vapor drum and inlet to tube bundle Both B & C Is economical in operation Employs high velocity, high heat transfer rate and less heating surface requirement Employs a centrifugal pump placed between external downtake from vapor drum and inlet to tube bundle Both B & C ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The equivalent diameter for fluid flow through a channel of constant non-circular cross section of area 'A' is given by (where, P = perimeter of the channel in contact with the fluid) A/P √A 4 A/P 4 P/A A/P √A 4 A/P 4 P/A ANSWER DOWNLOAD EXAMIANS APP
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