Theory of Machine The Coriolis component of acceleration acts Perpendicular to the sliding surface Along the sliding surface At 45° to the sliding surface Parallel to the sliding surface Perpendicular to the sliding surface Along the sliding surface At 45° to the sliding surface Parallel to the sliding surface ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The direction of linear velocity of any point on a link with respect to another point on the same link is Perpendicular to the link joining the points Parallel to the link joining the points None of the listed here At 45° to the link joining the points Perpendicular to the link joining the points Parallel to the link joining the points None of the listed here At 45° to the link joining the points ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine V-belts are usually used for Short drives Long drives None of these Long and short drives Short drives Long drives None of these Long and short drives ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The acceleration of a particle at any instant has two components i.e. radial component and tangential component. These two components will be Inclined at 45° Perpendicular to each other Parallel to each other Opposite to each other Inclined at 45° Perpendicular to each other Parallel to each other Opposite to each other ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A rotor which is balanced statically but not dynamically is supported on two bearings L apart and at high speed of the rotor, reaction on the left bearing is R. The right side of the bearing is shifted to a new position 2L apart from the left bearing. At the same rotor speed, dynamic reaction on the left bearing in the new arrangement will Remain same as before Become equal to R/4 Become equal to R/2 Become equal to 2R Remain same as before Become equal to R/4 Become equal to R/2 Become equal to 2R ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a reciprocating steam engine, when the crank has turned from inner dead centre through an angle θ, the angular velocity of the connecting rod is given by ω sinθ/(n² - sin²θ)1/2 ω cosθ/(n² - sin²θ)1/2 ω cosθ/(n² - cos²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ω sinθ/(n² - sin²θ)1/2 ω cosθ/(n² - sin²θ)1/2 ω cosθ/(n² - cos²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ANSWER DOWNLOAD EXAMIANS APP
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