Theory of Machine The Coriolis component of acceleration acts Parallel to the sliding surface At 45° to the sliding surface Along the sliding surface Perpendicular to the sliding surface Parallel to the sliding surface At 45° to the sliding surface Along the sliding surface Perpendicular to the sliding surface ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Rectilinear motion of piston is converted into rotary by Gudgeon pin Connecting rod Cross head Slider crank Gudgeon pin Connecting rod Cross head Slider crank ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a multiple V-belt drive, if one of the belts is broken, then we should replace None of these The broken belt and the belts on either side of it The broken belt only All the belts None of these The broken belt and the belts on either side of it The broken belt only All the belts ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r cosθ m.ω².r sinθ m.ω².r (cos 2θ/n) m.ω².r (sin 2θ/n) m.ω².r cosθ m.ω².r sinθ m.ω².r (cos 2θ/n) m.ω².r (sin 2θ/n) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A rotor which is balanced statically but not dynamically is supported on two bearings L apart and at high speed of the rotor, reaction on the left bearing is R. The right side of the bearing is shifted to a new position 2L apart from the left bearing. At the same rotor speed, dynamic reaction on the left bearing in the new arrangement will Become equal to R/4 Become equal to R/2 Become equal to 2R Remain same as before Become equal to R/4 Become equal to R/2 Become equal to 2R Remain same as before ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The periodic time of one oscillation for a simple pendulum is 2π. √(l/g) 2π. √(g/l) (1/2π). √(l/g) (1/2π). √(g/l) 2π. √(l/g) 2π. √(g/l) (1/2π). √(l/g) (1/2π). √(g/l) ANSWER DOWNLOAD EXAMIANS APP