Theory of Machine Maximum fluctuation of energy in a flywheel is equal to [where I = Mass moment of inertia of the flywheel, E = Maximum fluctuation of energy, CS = Coefficient of fluctuation of speed, and ω = Mean angular speed = (ω₁ + ω₂)/2] I.ω².CS All of these 2.E.CS I.ω.(ω₁ - ω₂) I.ω².CS All of these 2.E.CS I.ω.(ω₁ - ω₂) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Coriolis component of acceleration acts Parallel to the sliding surface Along the sliding surface At 45° to the sliding surface Perpendicular to the sliding surface Parallel to the sliding surface Along the sliding surface At 45° to the sliding surface Perpendicular to the sliding surface ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The maximum fluctuation of speed is the Difference of the maximum and minimum speeds Difference of minimum fluctuation of speed and the mean speed Sum of maximum and minimum speeds Variations of speed above and below the mean resisting torque line Difference of the maximum and minimum speeds Difference of minimum fluctuation of speed and the mean speed Sum of maximum and minimum speeds Variations of speed above and below the mean resisting torque line ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a Hartnell governor, the lift of the sleeve is given by (where r₁ and r₂ = Max. and min. radii of rotation, x = Length of ball arm of the lever, and y = Length of sleeve arm of the lever) (r₁ - r₂) (y/x) (r₁ + r₂) (y/x) (r₁ + r₂) (x/y) (r₁ - r₂) (x/y) (r₁ - r₂) (y/x) (r₁ + r₂) (y/x) (r₁ + r₂) (x/y) (r₁ - r₂) (x/y) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a pantograph, all the pairs are Spherical pairs Sliding pairs Turning pairs Self-closed pairs Spherical pairs Sliding pairs Turning pairs Self-closed pairs ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The equivalent length of a simple pendulum which gives the same frequency as a compound pendulum is h/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h h²/(kG² + h²) h/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h h²/(kG² + h²) ANSWER DOWNLOAD EXAMIANS APP
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