Theory of Machine A friction circle is a circle drawn when a journal rotates in a bearing. Its radius depends upon the coefficient of friction and the Clearance between journal and bearing Angular velocity of journal Radius of journal Magnitude of the forces on journal Clearance between journal and bearing Angular velocity of journal Radius of journal Magnitude of the forces on journal ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The natural frequency of free torsional vibrations of a shaft is equal to (where q = Torsional stiffness of the shaft, and I = Mass moment of inertia of the disc attached at the end of a shaft) 1/2π 2π. √(q/I) (1/2π). √(q/I) 2π qI 1/2π 2π. √(q/I) (1/2π). √(q/I) 2π qI ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine For a kinematic chain to be considered as mechanism One link should be fixed There is no such criterion None of the links should be fixed Two links should be fixed One link should be fixed There is no such criterion None of the links should be fixed Two links should be fixed ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In order to facilitate starting of locomotive in any position, the cranks of a locomotive with two cylinders, are placed at 120° to each other 45° to each other 180° to each other 90° to each other 120° to each other 45° to each other 180° to each other 90° to each other ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A shaft has two heavy rotors mounted on it. The transverse natural frequencies, considering each of the rotor separately, are 100 Hz and 200 Hz respectively. The lowest critical speed is 12,000 r.p.m. 5,367 r.p.m. 6,000 r.p.m. 9,360 r.p.m. 12,000 r.p.m. 5,367 r.p.m. 6,000 r.p.m. 9,360 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ (l₁ + l₂ + l₃)/3 l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ (l₁ + l₂ + l₃)/3 ANSWER DOWNLOAD EXAMIANS APP
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