Theory of Machine Klein's construction can be used to determine acceleration of various parts when the crank is at All of the listed here Right angles to the link of the stroke Inner dead centre Outer dead centre All of the listed here Right angles to the link of the stroke Inner dead centre Outer dead centre ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A governor is said to be stable, if the Radius of rotation of balls increases as the equilibrium speed increases Radius of rotation of balls decreases as the equilibrium speed decreases Radius of rotation of balls increases as the equilibrium speed decreases Radius of rotation of balls decreases as the equilibrium speed increases Radius of rotation of balls increases as the equilibrium speed increases Radius of rotation of balls decreases as the equilibrium speed decreases Radius of rotation of balls increases as the equilibrium speed decreases Radius of rotation of balls decreases as the equilibrium speed increases ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Elements of pairs held together mechanically is known as Mechanical pair Open pair Closed pair Rolling pair Mechanical pair Open pair Closed pair Rolling pair ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Which gear is used for connecting two coplanar and intersecting shafts? Spur gear Bevel gear Helical gear None of these Spur gear Bevel gear Helical gear None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine If the rotating mass of a rim type flywheel is distributed on another rim type flywheel whose mean radius is half the mean radius of the former, then energy stored in the latter at the same speed will be Same as the first one One fourth of the first one One and a half times the first one Four times the first one Same as the first one One fourth of the first one One and a half times the first one Four times the first one ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 3(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h ANSWER DOWNLOAD EXAMIANS APP