Theory of Machine In locomotives, the ratio of the connecting rod length to me crank radius is kept very large in order to Minimize the effect of primary forces To start the locomotive quickly Have perfect balancing Minimize the effect of secondary forces Minimize the effect of primary forces To start the locomotive quickly Have perfect balancing Minimize the effect of secondary forces ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In the below figure, PC is the connecting rod and OC is the crank making an angle θ with the line of stroke PO and rotates with uniform angular velocity at ω rad/s. The Klien's acceleration diagram for determining the acceleration of the piston P is shown by quadrilateral CQNO, if N coincides with O, then Acceleration and velocity of the piston P is maximum Acceleration of the piston P is zero and its velocity is maximum Acceleration and velocity of the piston P is zero Acceleration of the piston P is maximum and its velocity is zero Acceleration and velocity of the piston P is maximum Acceleration of the piston P is zero and its velocity is maximum Acceleration and velocity of the piston P is zero Acceleration of the piston P is maximum and its velocity is zero ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The tractive force in a locomotive with two cylinders is given by (where c = Fraction of reciprocating parts per cylinder, m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, and θ = Angle of inclination of crank to the line of stroke) m.ω².r cosθ m.ω².r (cosθ - sinθ) m.ω².r sinθ (1 - c).m.ω².r (cosθ - sinθ) m.ω².r cosθ m.ω².r (cosθ - sinθ) m.ω².r sinθ (1 - c).m.ω².r (cosθ - sinθ) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Transmission angle is the angle between Output link and fixed link Output link and coupler Input link and coupler Input link and fixed link Output link and fixed link Output link and coupler Input link and coupler Input link and fixed link ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ (l₁ + l₂ + l₃)/3 l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ (l₁ + l₂ + l₃)/3 l₁ + l₂ + l₃ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The partial balancing of reciprocating parts in locomotives produces Hammer blow Variation in tractive force along the line of stroke All of these Swaying couple Hammer blow Variation in tractive force along the line of stroke All of these Swaying couple ANSWER DOWNLOAD EXAMIANS APP