Theory of Machine The Coriolis component of acceleration exists whenever a point moves along a path that has Tangential acceleration Linear displacement Rotational motion Gravitational acceleration Tangential acceleration Linear displacement Rotational motion Gravitational acceleration ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frequency of oscillation of a compound pendulum is 2π. √[(kG² + h²)/gh] (1/2π). √[gh/(kG² + h²)] (1/2π). √[(kG² + h²)/gh] 2π. √[gh/(kG² + h²)] 2π. √[(kG² + h²)/gh] (1/2π). √[gh/(kG² + h²)] (1/2π). √[(kG² + h²)/gh] 2π. √[gh/(kG² + h²)] ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Rectilinear motion of piston is converted into rotary by Slider crank Cross head Connecting rod Gudgeon pin Slider crank Cross head Connecting rod Gudgeon pin ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The advantage of the piston valve over the slide valve is that in the former case Power absorbed is less The pressure developed being high provides tight sealing Both wear and power absorbed are low Wear is less Power absorbed is less The pressure developed being high provides tight sealing Both wear and power absorbed are low Wear is less ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a flat collar bearing, considering uniform pressure, is (where r₁ and r₂ = External and internal radii of collar respectively) (1/2). μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3). μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3). μ W (r₁ + r₂) (1/2). μ W (r₁ + r₂) (1/2). μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3). μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3). μ W (r₁ + r₂) (1/2). μ W (r₁ + r₂) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ ANSWER DOWNLOAD EXAMIANS APP
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