Theory of Machine Lower pairs are those which have Surface contact between the two elements when in motion Elements of pairs not held together mechanically Point or line contact between the two elements when in motion Two elements that permit relative motion Surface contact between the two elements when in motion Elements of pairs not held together mechanically Point or line contact between the two elements when in motion Two elements that permit relative motion ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a four-bar chain it is required to give an oscillatory motion to the follower for a continuous rotation of the crank. For the lengths of 50 mm of crank and 70 mm of the follower, determine theoretical maximum length of coupler. The distance between fixed pivots of crank and followers is Slightly more than 95 mm Slightly less than 95 mm 45 mm 95 mm Slightly more than 95 mm Slightly less than 95 mm 45 mm 95 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The periodic time of one oscillation for a simple pendulum is 2π. √(l/g) (1/2π). √(l/g) (1/2π). √(g/l) 2π. √(g/l) 2π. √(l/g) (1/2π). √(l/g) (1/2π). √(g/l) 2π. √(g/l) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When a mass of a critically damped single degree of freedom system is deflected from its equilibrium position and released, then it will Return to equilibrium position without oscillation Oscillate with increasing time period Oscillate with constant amplitude Oscillate with decreasing amplitude Return to equilibrium position without oscillation Oscillate with increasing time period Oscillate with constant amplitude Oscillate with decreasing amplitude ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the radius of rotation of balls __________ as the equilibrium speed increases, the governor is said to be unstable. None of these Decreases Increases Remains constant None of these Decreases Increases Remains constant ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 2(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS