Theory of Machine In higher pair, the relative motion is Purely sliding Combination of sliding and turning Purely rotary Purely turning Purely sliding Combination of sliding and turning Purely rotary Purely turning ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as Simple pendulum Second's pendulum Compound pendulum Torsional pendulum Simple pendulum Second's pendulum Compound pendulum Torsional pendulum ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a flat collar bearing, considering uniform wear, is (where r₁ and r₂ = External and internal radii of collar respectively) (2/3) μ W (r₁ + r₂) (1/2) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2) μ W (r₁ + r₂) (2/3) μ W (r₁ + r₂) (1/2) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2) μ W (r₁ + r₂) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a four-bar chain it is required to give an oscillatory motion to the follower for a continuous rotation of the crank. For the lengths of 50 mm of crank and 70 mm of the follower, determine theoretical maximum length of coupler. The minimum length of the coupler will be 95 mm 45 mm Slightly more than 45 mm Slightly less than 45 mm 95 mm 45 mm Slightly more than 45 mm Slightly less than 45 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A body having moment of inertia o:m2 is rotating at 210 RPM and r with another body at rest having I 40 kg m2. The resultant speed after ing will be data are insufficient 90 RPM 80 RPM 100 RPM data are insufficient 90 RPM 80 RPM 100 RPM ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is (l₁ + l₂ + l₃)/3 l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ (l₁ + l₂ + l₃)/3 l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS