Theory of Machine If ω/ωn is very high for a body vibrating under steady state vibrations, the phase angle for all values of damping factors, will tend to approach 90° 0° 360° 180° 90° 0° 360° 180° ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A spring controlled governor is found unstable. It can be made stable by Decreasing the spring stiffness Increasing the ball mass Decreasing the ball mass Increasing the spring stiffness Decreasing the spring stiffness Increasing the ball mass Decreasing the ball mass Increasing the spring stiffness ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a band and block brake, the ratio of tensions on tight side and slack side of the band is (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the center of drum, and n = Number of blocks) T₁/T₂ = [(1 - μ tanθ)/(1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/(1 - μ tanθ)]n T₁/T₂ = μ. θ. n T₁/T₂ = (μ θ)n T₁/T₂ = [(1 - μ tanθ)/(1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/(1 - μ tanθ)]n T₁/T₂ = μ. θ. n T₁/T₂ = (μ θ)n ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Bifilar suspension method is used to determine Position of balancing weights Moment of inertia Natural frequency of vibration Centripetal acceleration Position of balancing weights Moment of inertia Natural frequency of vibration Centripetal acceleration ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A simple spring-mass vibrating system has a natural frequency of fn. If the spring stiffness is halved and the mass is doubled, then the natural frequency will become fn/2 4 fn 8 fn 2 fn fn/2 4 fn 8 fn 2 fn ANSWER DOWNLOAD EXAMIANS APP
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