Machine Design If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension) ⅟₂× (P1 + P2) [(√P1 + √P2)/2]² P1 + P2 [⅟₂ × (P1 + P2)] + Pc ⅟₂× (P1 + P2) [(√P1 + √P2)/2]² P1 + P2 [⅟₂ × (P1 + P2)] + Pc ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a marine flange coupling, the thickness of flange is taken as 3d/4 d/2 d/4 d/3 3d/4 d/2 d/4 d/3 ANSWER DOWNLOAD EXAMIANS APP
Machine Design The efficiency of a riveted joint is equal to Pc /P Ps /P Pt /P Least of Pt, Ps and Pc/P Pc /P Ps /P Pt /P Least of Pt, Ps and Pc/P ANSWER DOWNLOAD EXAMIANS APP
Machine Design The taper on cotter varies from 1 in 48 to 1 in 24 1 in 32 to 1 in 24 1 in 15 to 1 in 10 1 in 24 to 1 in 20 1 in 48 to 1 in 24 1 in 32 to 1 in 24 1 in 15 to 1 in 10 1 in 24 to 1 in 20 ANSWER DOWNLOAD EXAMIANS APP
Machine Design The notch sensitivity q is expressed in terms of fatigue stress concentration factor Kf and theoretical stress concentration factor Kt as (Kf + 1)/ (Kt + 1) (Kt - 1)/ (Kf - 1) (Kt + 1)/ (Kf + 1) (Kf - 1)/ (Kt - 1) (Kf + 1)/ (Kt + 1) (Kt - 1)/ (Kf - 1) (Kt + 1)/ (Kf + 1) (Kf - 1)/ (Kt - 1) ANSWER DOWNLOAD EXAMIANS APP
Machine Design A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is τ. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be τ τ/2 4 τ 2 τ τ τ/2 4 τ 2 τ ANSWER DOWNLOAD EXAMIANS APP
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