Machine Design
If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension)

[(√P1 + √P2)/2]²
[⅟₂ × (P1 + P2)] + Pc
⅟₂× (P1 + P2)
P1 + P2

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Machine Design
Plastic flow in ductile materials

Has no effect on it
Depends on other considerations
Lessens the seriousness of static loading stress concentration
Increases the seriousness of static loading stress concentration

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Machine Design
The cracks in helical springs used in railway carriages usually start on the inner side of the coil because of the fact that

It is subjected to a higher stress than the outer side
It is more stretched than the outer side during the manufacturing process
It has a lower curvature than the outer side
It is subjected to a higher cyclic loading than the outer side

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