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MGVCL Exam Paper (30-07-2021 Shift 1)

MGVCL Exam Paper (30-07-2021 Shift 1)
Calculate the capacitance per meter of a 50 Ω load cable that has an inductance of 50 nH/m.

30 pF
10 pF
20 pF
40 pF

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Z = √(L/C)
C = L/Z²
C = 50*10⁻⁹/(50*50)
C = 0.02 nF
C = 20 pF

MGVCL Exam Paper (30-07-2021 Shift 1)
In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors)

(A) Bubin together with / (B) her parents are coming / (C) to attend the party. / (D) NO ERROR

C
A
B
D

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
Which of the following features of Microsoft Word automatically moves to the next line while reaching the end of current line?

Carriage return
None of these
Enter
Word wrap

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
An electric potential field is produced in air by point 1 μC and 4 μC located at (-2, 1, 5) and (1, 3, -1) respectively. The energy stored in the field is

12.50 mJ
5.14 mJ
2.57 mJ
10.28 mJ

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
Choose the word which best expresses the similar meaning of the given word " CALLOW"

Mature
Calm
Immature
Sophisticated

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 1)
By inserting a plate of dielectric material between the plates of a parallel plate capacitor at constant potential, the energy stored in the capacitor is increased five times. The dielectric constant of the material is

25
1/25
1/5
5

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Energy stored by capacitor, Q = ½CV²
Dielectric constant is directly proportional to C and capacitance is proportional to the dielectrical constant

MORE MCQ ON MGVCL Exam Paper (30-07-2021 Shift 1)

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