MGVCL Exam Paper (30-07-2021 Shift 1) જ્વાળા: ધુમાડો:: બરફ : ___ ગરમી શીતળતા બાષ્પ તાપમાન ગરમી શીતળતા બાષ્પ તાપમાન ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) What is the full form of the acronym 'BCCI' in sports? Board of Common Cricket in International Board of Cricket Commentary in International Board of Cricket Committee in India Board of Control for Cricket in India Board of Common Cricket in International Board of Cricket Commentary in International Board of Cricket Committee in India Board of Control for Cricket in India ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The air envelope surrounding the earth is called ___ Lithosphere Hydrosphere Asthenosphere Atmosphere Lithosphere Hydrosphere Asthenosphere Atmosphere ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) While selecting the gas for a circuit breaker, the property of gas that should be considered is its(i) dielectric strength(ii) non-inflammability(iii) non-toxicity (i) and (ii) only (i), (ii) and (iii) (i) and (iii) only (i) only (i) and (ii) only (i), (ii) and (iii) (i) and (iii) only (i) only ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Properties of gas while selecting circuit breaker,1. Dielectric strength.2. Thermal conductivity.3. Arc quenching.4. Electrical properties.5. Chemical properties. Toxicity of arc products.
MGVCL Exam Paper (30-07-2021 Shift 1) Recently, India signed first ever term contract to import crude oil with which country? Japan Nepal Russia China Japan Nepal Russia China ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
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