MGVCL Exam Paper (30-07-2021 Shift 1) જ્વાળા: ધુમાડો:: બરફ : ___ બાષ્પ ગરમી તાપમાન શીતળતા બાષ્પ ગરમી તાપમાન શીતળતા ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A transformer designed for operation at 60 Hz supply is working at 50 Hz supply system without changing its voltage and current ratings. Compared to the full load efficiency at 60 Hz, the full load transformer efficiency at 50 Hz. decreases marginally remains unaltered increases by 30% increases marginally decreases marginally remains unaltered increases by 30% increases marginally ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 300 kW 450 kW 150 kW 600 kW 300 kW 450 kW 150 kW 600 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
MGVCL Exam Paper (30-07-2021 Shift 1) The Prime Minister Rozgar Yojana (PMRY) was launched in which year? 1995 1993 2005 2003 1995 1993 2005 2003 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Rearrange the following to form a meaningful sentence and find the most logical order from the given options.P: 60 countries using dance as a tool forQ: building social cohesion and resolvingR: conflict throughout the worldS: battery Dance has travelled far and wide across PQRS PQSR SPRQ SPQR PQRS PQSR SPRQ SPQR ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An eight-pole wave-connected armature has 600 conductors and is driven at 625 rev/min. If the flux per pole is 20 mWb, determine the generated emf. 325 V 500 V 125 V 250 V 325 V 500 V 125 V 250 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let,E→EMF in voltφ→Flux in weberA→Parallel path (for wave winding = 2)Z→No. of armature conductorsN→speed in rpmP = Number of polesE = PφNZ/(60A)E = 8*0.020*625/(60*2)E = 500 V
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