MGVCL Exam Paper (30-07-2021 Shift 1) A ___ is a device that forwards packets between networks by processing the routing information included in the packet. Bridge all the mentioned above Firewall Router Bridge all the mentioned above Firewall Router ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) If a 415 V, 50 Hz, star-connected, three-phase squirrel-cage induction motor is operated from a 415 V, 70 Hz supply, the torque that the motor can now provide while drawing rated current from the supply increases reduces increases or reduces depending upon the rotor resistance remains the same increases reduces increases or reduces depending upon the rotor resistance remains the same ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Choose the best option from the given alternatives which can be substituted for the given word/sentenceA disease prevailing in a locality Endemic Habitat Host Epic Endemic Habitat Host Epic ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) 1 terabyte is equal to 1024 gigabytes 1024 kilobytes None of these 1024 bytes 1024 gigabytes 1024 kilobytes None of these 1024 bytes ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) While selecting the gas for a circuit breaker, the property of gas that should be considered is its(i) dielectric strength(ii) non-inflammability(iii) non-toxicity (i), (ii) and (iii) (i) and (ii) only (i) and (iii) only (i) only (i), (ii) and (iii) (i) and (ii) only (i) and (iii) only (i) only ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Properties of gas while selecting circuit breaker,1. Dielectric strength.2. Thermal conductivity.3. Arc quenching.4. Electrical properties.5. Chemical properties. Toxicity of arc products.
MGVCL Exam Paper (30-07-2021 Shift 1) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series aiding. 932 mH 1270 mH 1135 mH 730 mH 932 mH 1270 mH 1135 mH 730 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance (M) = k*√(L1*L2)k = 0.45M = 0.45*√(900*100*10⁻⁶) = 135 mHLeq = L1 + L2 + 2MLeq = 900 + 100 + 270Leq = 1270 mH
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