MGVCL Exam Paper (30-07-2021 Shift 1) In computer networks, the nodes are the computer that terminates data the computer that routes data the computer that originates data all the mentioned above the computer that terminates data the computer that routes data the computer that originates data all the mentioned above ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An eight-pole wave-connected armature has 600 conductors and is driven at 625 rev/min. If the flux per pole is 20 mWb, determine the generated emf. 500 V 325 V 125 V 250 V 500 V 325 V 125 V 250 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let,E→EMF in voltφ→Flux in weberA→Parallel path (for wave winding = 2)Z→No. of armature conductorsN→speed in rpmP = Number of polesE = PφNZ/(60A)E = 8*0.020*625/(60*2)E = 500 V
MGVCL Exam Paper (30-07-2021 Shift 1) The term NEFT (in banking), is an abbreviation of ___ Net Electronics Financial Transfer National Electronics Financial Transaction Net Electronics Funds Transfer National Electronic Funds Transfer Net Electronics Financial Transfer National Electronics Financial Transaction Net Electronics Funds Transfer National Electronic Funds Transfer ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The frequency of the emf in the stator of a 4-pole induction motor is 50 Hz, and that in the rotor is 2 Hz. What is the slip and at what speed is the motor running? 4%, 1455 rpm 3%, 1440 rpm 4%, 1440 rpm 3%, 1455 rpm 4%, 1455 rpm 3%, 1440 rpm 4%, 1440 rpm 3%, 1455 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rotor frequency, f_r = s*f_ss = 2/50s = 0.04Ns = 120f/PNs = 1500 rpms = (Ns - Nr)/NsNr = Ns(1 - s)Nr = 1500*(1 - 0.04)Nr = 1440 rpm
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 300 kW 450 kW 150 kW 600 kW 300 kW 450 kW 150 kW 600 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Dimnished Ambience Benifited Suppresed Dimnished Ambience Benifited Suppresed ANSWER DOWNLOAD EXAMIANS APP
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