MGVCL Exam Paper (30-07-2021 Shift 1) In computer networks, the nodes are the computer that terminates data all the mentioned above the computer that originates data the computer that routes data the computer that terminates data all the mentioned above the computer that originates data the computer that routes data ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Dena Bank and Vijaya Bank recenlty got merged with which of the following banks? Bank of Baroda Indian Overseas Bank Punjab National Bank State Bank of India Bank of Baroda Indian Overseas Bank Punjab National Bank State Bank of India ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The frequency of the emf in the stator of a 4-pole induction motor is 50 Hz, and that in the rotor is 2 Hz. What is the slip and at what speed is the motor running? 4%, 1440 rpm 3%, 1440 rpm 4%, 1455 rpm 3%, 1455 rpm 4%, 1440 rpm 3%, 1440 rpm 4%, 1455 rpm 3%, 1455 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rotor frequency, f_r = s*f_ss = 2/50s = 0.04Ns = 120f/PNs = 1500 rpms = (Ns - Nr)/NsNr = Ns(1 - s)Nr = 1500*(1 - 0.04)Nr = 1440 rpm
MGVCL Exam Paper (30-07-2021 Shift 1) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 15 Ω and the resistance of the resistor connected to the sound core was 45 Ω. Calculate the distance of the fault point from the test end. 150 m 75 m 225 m 450 m 150 m 75 m 225 m 450 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (15/60)*600= 150 m
MGVCL Exam Paper (30-07-2021 Shift 1) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series aiding. 932 mH 730 mH 1270 mH 1135 mH 932 mH 730 mH 1270 mH 1135 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance (M) = k*√(L1*L2)k = 0.45M = 0.45*√(900*100*10⁻⁶) = 135 mHLeq = L1 + L2 + 2MLeq = 900 + 100 + 270Leq = 1270 mH
MGVCL Exam Paper (30-07-2021 Shift 1) માણસ: ઘર :: પશુ : અંતરિક્ષ પાતાળ ગુફા આકાશ અંતરિક્ષ પાતાળ ગુફા આકાશ ANSWER DOWNLOAD EXAMIANS APP
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