MGVCL Exam Paper (30-07-2021 Shift 1) 1.મંગલ + આચરણ - મંગલાચરણ2. હરિ+ઇન્દ્ર - હરીન્દ્ર3.નર+ઈશ - નરેશ4. પ્રતિ+અક્ષ - પ્રતિક્ષઉપરોક્ત વર્ણવેલમાંથી કઈ સંધિ સાચી છે. 1,3 1,4 2,1 2,3, 1,3 1,4 2,1 2,3, ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 375 W and –50 W. Calculate the reactive power taken by the load. 425√3 VAR 325/√3 VAR 425/√3 VAR 325√3 VAR 425√3 VAR 325/√3 VAR 425/√3 VAR 325√3 VAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Reactive power taken, Q = √3*(W1 - W2)Q = √3*(375 + 50)Q = √3*425 kVAR
MGVCL Exam Paper (30-07-2021 Shift 1) The expression for voltage regulation of a short transmission line for lagging power factor is given by: ___, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resistance and 'X' is the line reactance. (IR cosφ_r + IX sinφ_r)/V_r (IR cosφ_r - IX sinφ_r)/V_r (IX cosφ_r - IR sinφ_r)/V_r (IX cosφ_r + IR sinφ_r)/V_r (IR cosφ_r + IX sinφ_r)/V_r (IR cosφ_r - IX sinφ_r)/V_r (IX cosφ_r - IR sinφ_r)/V_r (IX cosφ_r + IR sinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + Ixsinφ)/VrFor leading power factor = (IR*cosφ - Ixsinφ)/VrZero voltage regulation occurs on leading power factor only.
MGVCL Exam Paper (30-07-2021 Shift 1) Who has won the ‘World Games Athlete Of the Year 2019’ ? Marina Chernova Rani Rampal Rhea Stinn Stanislav Horuna Marina Chernova Rani Rampal Rhea Stinn Stanislav Horuna ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A fully controlled natural commutated 3-phase bridge rectifier is operating with a firing angle α = 30°, The peak to peak voltage ripple expressed as a ratio of the peak output dc voltage at the output of the converter bridge is √3 -1 √3-1 1-(√3/2) 0.5 √3 -1 √3-1 1-(√3/2) 0.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,φ is firing angleVoltage ripple for 3-phase bridge rectifier = cos(φ) = Cos(30)= 1/2
MGVCL Exam Paper (30-07-2021 Shift 1) A given solar cell has the following specifications:Open-circuit voltage, Voc: 0.7 VShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AIf the solar cell operates at maximum power point, calculate the efficiency. 13.70% 12.70% 14.70% 15.70% 13.70% 12.70% 14.70% 15.70% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation is given by:Efficiency = (F.F*Voc*Isc)/Pin= (0.6*3.5*0.7)/10= 0.14702% efficiency = 14.7 %
EXAMIANS