MGVCL Exam Paper (30-07-2021 Shift 1) Who has won the ‘World Games Athlete Of the Year 2019’ ? Rhea Stinn Rani Rampal Stanislav Horuna Marina Chernova Rhea Stinn Rani Rampal Stanislav Horuna Marina Chernova ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) મારુતારુંનો ઝગડો હજી ખતમ થયો નથી, ચારપાંચ વર્ષ થઇ ગયા અને રાતદિવસ સાથે ઉઠવા-બેસવાનું તો ચાલુ જ છે. ઉપરોક્ત વાક્યમાં ક્યા ક્યા વ્યાકરણીય સમાસનો ઉપયોગ કરાયો છે? દ્વન્દ્વ, મધ્યમપદલોપી દ્વન્દ્વ તત્પુરુષ, અવ્યવીભાવ, મધ્યમપદલોપી દ્વન્દ્વ, મધ્યમપદલોપી દ્વન્દ્વ તત્પુરુષ, અવ્યવીભાવ, મધ્યમપદલોપી ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The air envelope surrounding the earth is called ___ Hydrosphere Lithosphere Atmosphere Asthenosphere Hydrosphere Lithosphere Atmosphere Asthenosphere ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Dimnished Suppresed Ambience Benifited Dimnished Suppresed Ambience Benifited ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Case 1: The PV connected to the DC bus was injecting 20 kW of power constituting of 1 kW of lossCase 2: The same PV is connected to the AC bus constituting to 1.5 kW loss. Find out the change in efficiency from Case 1 to Case 2? 5% decrease 5% increase 2.5% decrease 2.5% increase 5% decrease 5% increase 2.5% decrease 2.5% increase ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In DC microgrid system,Efficiency α 1/PinFor 1 kW loss injecting power is 20 kWFor 1.5 kW loss injecting power will be proportional to 30 kWSo,Efficiency will be reduced 0.025
MGVCL Exam Paper (30-07-2021 Shift 1) A given solar cell has the following specifications:Open-circuit voltage, Voc: 0.7 VShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AIf the solar cell operates at maximum power point, calculate the efficiency. 15.70% 13.70% 12.70% 14.70% 15.70% 13.70% 12.70% 14.70% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation is given by:Efficiency = (F.F*Voc*Isc)/Pin= (0.6*3.5*0.7)/10= 0.14702% efficiency = 14.7 %