MGVCL Exam Paper (30-07-2021 Shift 1) Who has won the ‘World Games Athlete Of the Year 2019’ ? Rani Rampal Stanislav Horuna Rhea Stinn Marina Chernova Rani Rampal Stanislav Horuna Rhea Stinn Marina Chernova ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The expression for voltage regulation of a short transmission line for lagging power factor is given by: ___, where, 'I' is the line current, 'V_r' is the receiving end voltage, 'R' is the line resistance and 'X' is the line reactance. (IR cosφ_r + IX sinφ_r)/V_r (IX cosφ_r - IR sinφ_r)/V_r (IX cosφ_r + IR sinφ_r)/V_r (IR cosφ_r - IX sinφ_r)/V_r (IR cosφ_r + IX sinφ_r)/V_r (IX cosφ_r - IR sinφ_r)/V_r (IX cosφ_r + IR sinφ_r)/V_r (IR cosφ_r - IX sinφ_r)/V_r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For lagging power factor = (IR*cosφ + Ixsinφ)/VrFor leading power factor = (IR*cosφ - Ixsinφ)/VrZero voltage regulation occurs on leading power factor only.
MGVCL Exam Paper (30-07-2021 Shift 1) The miniature circuit breaker (MCB) shown in figure is two pole MCB three pole MCB five pole MCB four pole MCB two pole MCB three pole MCB five pole MCB four pole MCB ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following features of Microsoft Word automatically moves to the next line while reaching the end of current line? Word wrap None of these Carriage return Enter Word wrap None of these Carriage return Enter ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 300 kW 450 kW 600 kW 150 kW 300 kW 450 kW 600 kW 150 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
MGVCL Exam Paper (30-07-2021 Shift 1) Calculate the capacitance per meter of a 50 Ω load cable that has an inductance of 50 nH/m. 40 pF 10 pF 20 pF 30 pF 40 pF 10 pF 20 pF 30 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Z = √(L/C)C = L/Z²C = 50*10⁻⁹/(50*50)C = 0.02 nFC = 20 pF
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