MGVCL Exam Paper (30-07-2021 Shift 1) Choose the best option from the given alternatives which can be substituted for the given word/sentenceA disease prevailing in a locality Host Epic Endemic Habitat Host Epic Endemic Habitat ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) ___ is the process of actuating equipment operation at remote locations. Data acquisition Data processing Supervisory control Supplementary control Data acquisition Data processing Supervisory control Supplementary control ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A transformer designed for operation at 60 Hz supply is working at 50 Hz supply system without changing its voltage and current ratings. Compared to the full load efficiency at 60 Hz, the full load transformer efficiency at 50 Hz. increases marginally decreases marginally increases by 30% remains unaltered increases marginally decreases marginally increases by 30% remains unaltered ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An eight-pole wave-connected armature has 600 conductors and is driven at 625 rev/min. If the flux per pole is 20 mWb, determine the generated emf. 325 V 500 V 250 V 125 V 325 V 500 V 250 V 125 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let,E→EMF in voltφ→Flux in weberA→Parallel path (for wave winding = 2)Z→No. of armature conductorsN→speed in rpmP = Number of polesE = PφNZ/(60A)E = 8*0.020*625/(60*2)E = 500 V
MGVCL Exam Paper (30-07-2021 Shift 1) In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors)(A) Bubin together with / (B) her parents are coming / (C) to attend the party. / (D) NO ERROR D C B A D C B A ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Calculate the capacitance per meter of a 50 Ω load cable that has an inductance of 50 nH/m. 20 pF 30 pF 10 pF 40 pF 20 pF 30 pF 10 pF 40 pF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Z = √(L/C)C = L/Z²C = 50*10⁻⁹/(50*50)C = 0.02 nFC = 20 pF
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