MGVCL Exam Paper (30-07-2021 Shift 1) What is the largest thermal power plant in India? Mundra Thermal Power Station Sasan Ultra Mega Power Plant Vindhyachal Thermal Power Station Talcher Super Thermal Power Station Mundra Thermal Power Station Sasan Ultra Mega Power Plant Vindhyachal Thermal Power Station Talcher Super Thermal Power Station ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Tank - Name of power station - capacity1 - Vindhyachal Thermal Power Station - 4,760MW.2 - Mundra Thermal Power Station - 4620 MW3 - The Sasan Ultra Mega power plant - 3960 MW4 - The Tiroda thermal power plant - 3300 MW
MGVCL Exam Paper (30-07-2021 Shift 1) Replace the underlined phrase in braket grammatically and conceptually with the help of the given options. If the given sentence is correct then select the option 'The given sentence is correct'.The new client had to pay money to initiates a account and activate their service have to pay money to initiate an had to pay money to initiate an had to pay money to initiate a The given sentence is correct have to pay money to initiate an had to pay money to initiate an had to pay money to initiate a The given sentence is correct ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Rearrange the following to form a meaningful sentence and find the most logical order from the given options.P: 60 countries using dance as a tool forQ: building social cohesion and resolvingR: conflict throughout the worldS: battery Dance has travelled far and wide across PQSR PQRS SPQR SPRQ PQSR PQRS SPQR SPRQ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series aiding. 1135 mH 1270 mH 932 mH 730 mH 1135 mH 1270 mH 932 mH 730 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance (M) = k*√(L1*L2)k = 0.45M = 0.45*√(900*100*10⁻⁶) = 135 mHLeq = L1 + L2 + 2MLeq = 900 + 100 + 270Leq = 1270 mH
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
MGVCL Exam Paper (30-07-2021 Shift 1) A given solar cell has the following specifications:Open-circuit voltage, Voc: 0.7 VShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AIf the solar cell operates at maximum power point, calculate the efficiency. 14.70% 15.70% 12.70% 13.70% 14.70% 15.70% 12.70% 13.70% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation is given by:Efficiency = (F.F*Voc*Isc)/Pin= (0.6*3.5*0.7)/10= 0.14702% efficiency = 14.7 %
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