MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which expresses nearly the opposite meaning of the given word "QUANDARY " Embarrassment Clutch Certainty Dilemma Embarrassment Clutch Certainty Dilemma ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Recently, Dr. Subir Vithal Gokarn passed away due to illness. He is a/an ___ Former Finance Minister Former RBI Deputy Governor Former IAS Officer Former Chief Minister of Gujarat Former Finance Minister Former RBI Deputy Governor Former IAS Officer Former Chief Minister of Gujarat ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) ___ is the process of actuating equipment operation at remote locations. Data acquisition Data processing Supplementary control Supervisory control Data acquisition Data processing Supplementary control Supervisory control ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following is the layer of a computer system between the hardware and the user program? System Environment None of these Application Software Operating System System Environment None of these Application Software Operating System ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An RLC series circuit consists of R = 16 Ω, L = 5 mH and C = 2 μF. Calculate the quality factor. 2.125 4.125 5.125 3.125 2.125 4.125 5.125 3.125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For series RLC circuit,Q = (1/R)*√(L/C)Q = 1/16*√(5 mH/2 μF)Q = 50/16Q = 3.125
MGVCL Exam Paper (30-07-2021 Shift 1) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 15 Ω and the resistance of the resistor connected to the sound core was 45 Ω. Calculate the distance of the fault point from the test end. 225 m 75 m 150 m 450 m 225 m 75 m 150 m 450 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (15/60)*600= 150 m
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