MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which expresses nearly the opposite meaning of the given word "QUANDARY " Clutch Embarrassment Dilemma Certainty Clutch Embarrassment Dilemma Certainty ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Suppresed Benifited Ambience Dimnished Suppresed Benifited Ambience Dimnished ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A ___ is a device that forwards packets between networks by processing the routing information included in the packet. Firewall Bridge all the mentioned above Router Firewall Bridge all the mentioned above Router ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) નીચેના રુઢિપ્રયોગોને અર્થ સાથે સાંકળી જોડી બનાવો.1. કાન કરડવા - 1. બાતમી મળી જવી.2. કાન ફૂંકવા - 2. વાત પર ધ્યાન ન આપવું.૩. કાને વાત પહોચવી - ૩. કાન 1-22-33-44-1 1-32-43-14-2 1-42-33-14-2 1-32-23-44-1 1-22-33-44-1 1-32-43-14-2 1-42-33-14-2 1-32-23-44-1 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An eight-pole wave-connected armature has 600 conductors and is driven at 625 rev/min. If the flux per pole is 20 mWb, determine the generated emf. 250 V 500 V 325 V 125 V 250 V 500 V 325 V 125 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let,E→EMF in voltφ→Flux in weberA→Parallel path (for wave winding = 2)Z→No. of armature conductorsN→speed in rpmP = Number of polesE = PφNZ/(60A)E = 8*0.020*625/(60*2)E = 500 V
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
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