MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which expresses nearly the opposite meaning of the given word "QUANDARY " Embarrassment Dilemma Certainty Clutch Embarrassment Dilemma Certainty Clutch ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Wrinkel Various Abolishid Absurrd Wrinkel Various Abolishid Absurrd ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following are the advantages of Aerial Bunched Cables (ABC)? All of these Elimination of theft of energy Reduced height of supports Higher safety and reliability All of these Elimination of theft of energy Reduced height of supports Higher safety and reliability ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors)(A) Bubin together with / (B) her parents are coming / (C) to attend the party. / (D) NO ERROR C A B D C A B D ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) While selecting the gas for a circuit breaker, the property of gas that should be considered is its(i) dielectric strength(ii) non-inflammability(iii) non-toxicity (i), (ii) and (iii) (i) only (i) and (iii) only (i) and (ii) only (i), (ii) and (iii) (i) only (i) and (iii) only (i) and (ii) only ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Properties of gas while selecting circuit breaker,1. Dielectric strength.2. Thermal conductivity.3. Arc quenching.4. Electrical properties.5. Chemical properties. Toxicity of arc products.
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 300 kW 450 kW 600 kW 150 kW 300 kW 450 kW 600 kW 150 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW