MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which expresses nearly the opposite meaning of the given word "QUANDARY " Embarrassment Clutch Dilemma Certainty Embarrassment Clutch Dilemma Certainty ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series aiding. 1135 mH 730 mH 932 mH 1270 mH 1135 mH 730 mH 932 mH 1270 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance (M) = k*√(L1*L2)k = 0.45M = 0.45*√(900*100*10⁻⁶) = 135 mHLeq = L1 + L2 + 2MLeq = 900 + 100 + 270Leq = 1270 mH
MGVCL Exam Paper (30-07-2021 Shift 1) Case 1: The PV connected to the DC bus was injecting 20 kW of power constituting of 1 kW of lossCase 2: The same PV is connected to the AC bus constituting to 1.5 kW loss. Find out the change in efficiency from Case 1 to Case 2? 5% decrease 2.5% decrease 5% increase 2.5% increase 5% decrease 2.5% decrease 5% increase 2.5% increase ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In DC microgrid system,Efficiency α 1/PinFor 1 kW loss injecting power is 20 kWFor 1.5 kW loss injecting power will be proportional to 30 kWSo,Efficiency will be reduced 0.025
MGVCL Exam Paper (30-07-2021 Shift 1) Dena Bank and Vijaya Bank recenlty got merged with which of the following banks? State Bank of India Indian Overseas Bank Bank of Baroda Punjab National Bank State Bank of India Indian Overseas Bank Bank of Baroda Punjab National Bank ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which best expresses the similar meaning of the given word " CALLOW" Calm Immature Mature Sophisticated Calm Immature Mature Sophisticated ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
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