MGVCL Exam Paper (30-07-2021 Shift 1) નીચે પૈકી 'અચરજ'નો પર્યાયી શબ્દ ક્યો છે? જગત શાશ્વત રજ વિસ્મય જગત શાશ્વત રજ વિસ્મય ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The necessary equation to be solved during the load flow analysis using Fast-Decoupled methid is given below:where B' and B'' are formed using the imaginary part of the bus admittance matrix Ybus, n is the total number of buses in the system, m is the number of voltage regulated buses. The size of matrix B' is∆P/|Vi|= -B' ∆δ∆Q/|Vi| = -B'' ∆|Vi| (n-m) x (n-m) (n-m-1) x (n-m-1) (n-1) x (n-1) (m-1) x (m-1) (n-m) x (n-m) (n-m-1) x (n-m-1) (n-1) x (n-1) (m-1) x (m-1) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In FDLF method,B' corresponds to susceptance of unknown of PQ and PV busOrder of B' matrix is = (n -1)*(n - 1)Where n is total no. of buses.Order of B'' = (n - m - 1)*(n - m - 1)
MGVCL Exam Paper (30-07-2021 Shift 1) What is the full form of the acronym 'BCCI' in sports? Board of Cricket Committee in India Board of Control for Cricket in India Board of Cricket Commentary in International Board of Common Cricket in International Board of Cricket Committee in India Board of Control for Cricket in India Board of Cricket Commentary in International Board of Common Cricket in International ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
MGVCL Exam Paper (30-07-2021 Shift 1) The term NEFT (in banking), is an abbreviation of ___ National Electronic Funds Transfer National Electronics Financial Transaction Net Electronics Funds Transfer Net Electronics Financial Transfer National Electronic Funds Transfer National Electronics Financial Transaction Net Electronics Funds Transfer Net Electronics Financial Transfer ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) In computer networks, the nodes are the computer that originates data the computer that terminates data the computer that routes data all the mentioned above the computer that originates data the computer that terminates data the computer that routes data all the mentioned above ANSWER DOWNLOAD EXAMIANS APP