MGVCL Exam Paper (30-07-2021 Shift 1) નીચે પૈકી 'અચરજ'નો પર્યાયી શબ્દ ક્યો છે? શાશ્વત જગત રજ વિસ્મય શાશ્વત જગત રજ વિસ્મય ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) જીવનમાં તડકોછાયો એતો એક ઘટમાળ છે.વાક્યમાં ક્યા સમાસનો ઉપયોગ કરવામાં આવ્યો છે? ઉપપદ તત્પુરુષ દ્વન્દ્વ કર્મધારય ઉપપદ તત્પુરુષ દ્વન્દ્વ કર્મધારય ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) માણસ: ઘર :: પશુ : ગુફા અંતરિક્ષ પાતાળ આકાશ ગુફા અંતરિક્ષ પાતાળ આકાશ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The air envelope surrounding the earth is called ___ Hydrosphere Lithosphere Asthenosphere Atmosphere Hydrosphere Lithosphere Asthenosphere Atmosphere ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0
MGVCL Exam Paper (30-07-2021 Shift 1) In computer networks, the nodes are the computer that terminates data the computer that routes data the computer that originates data all the mentioned above the computer that terminates data the computer that routes data the computer that originates data all the mentioned above ANSWER DOWNLOAD EXAMIANS APP
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