MGVCL Exam Paper (30-07-2021 Shift 1) નીચે પૈકી 'અચરજ'નો પર્યાયી શબ્દ ક્યો છે? રજ શાશ્વત વિસ્મય જગત રજ શાશ્વત વિસ્મય જગત ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The operating time of an inverse definite minimum time (IDMT) overcurrent relay corresponding to plug-setting multiplier (PSM) = 1 and time-multiplier setting (TMS) = 1 will be infinite zero 1 sec 3 sec infinite zero 1 sec 3 sec ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation of operating time for IDMT relay (t) = 0.14*TMS/[(PSM^0.02) - 1]Here,PSM = TMS = 1So,t = 0.14*1/(1 - 1)t = infinite
MGVCL Exam Paper (30-07-2021 Shift 1) The term NEFT (in banking), is an abbreviation of ___ National Electronics Financial Transaction National Electronic Funds Transfer Net Electronics Financial Transfer Net Electronics Funds Transfer National Electronics Financial Transaction National Electronic Funds Transfer Net Electronics Financial Transfer Net Electronics Funds Transfer ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 300 kW 450 kW 600 kW 150 kW 300 kW 450 kW 600 kW 150 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following are the advantages of Aerial Bunched Cables (ABC)? Elimination of theft of energy Reduced height of supports All of these Higher safety and reliability Elimination of theft of energy Reduced height of supports All of these Higher safety and reliability ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Three resistances 750 Ω, 600 Ω and 200 Ω are connected in parallel. The total current is 1 A. Determine the voltage applied. 125 V 150 V 200 V 100 V 125 V 150 V 200 V 100 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equivalent resistance of the circuit, Req = (750|| 600 || 200)Req = 125 ΩCurrent from source = 1 ASource voltage = 1*125Source voltage = 125 V
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