MGVCL Exam Paper (30-07-2021 Shift 1) 1 terabyte is equal to 1024 gigabytes 1024 bytes None of these 1024 kilobytes 1024 gigabytes 1024 bytes None of these 1024 kilobytes ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 150 kW 300 kW 600 kW 450 kW 150 kW 300 kW 600 kW 450 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
MGVCL Exam Paper (30-07-2021 Shift 1) A fully controlled natural commutated 3-phase bridge rectifier is operating with a firing angle α = 30°, The peak to peak voltage ripple expressed as a ratio of the peak output dc voltage at the output of the converter bridge is √3-1 0.5 √3 -1 1-(√3/2) √3-1 0.5 √3 -1 1-(√3/2) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,φ is firing angleVoltage ripple for 3-phase bridge rectifier = cos(φ) = Cos(30)= 1/2
MGVCL Exam Paper (30-07-2021 Shift 1) The power factor angle of a purely inductive circuit is 60° 45° 30° 90° 60° 45° 30° 90° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Power factor for purely inductive circuit is 0 and power factor angle is 90 degree.Power factor for purely capacitive circuit is 0 and power factor angle is 90 degreePower factor for purely resistive circuit is 1 and power factor angle is 0 degree
MGVCL Exam Paper (30-07-2021 Shift 1) Recently, Dr. Subir Vithal Gokarn passed away due to illness. He is a/an ___ Former IAS Officer Former Chief Minister of Gujarat Former Finance Minister Former RBI Deputy Governor Former IAS Officer Former Chief Minister of Gujarat Former Finance Minister Former RBI Deputy Governor ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) An RLC series circuit consists of R = 16 Ω, L = 5 mH and C = 2 μF. Calculate the quality factor. 5.125 3.125 4.125 2.125 5.125 3.125 4.125 2.125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For series RLC circuit,Q = (1/R)*√(L/C)Q = 1/16*√(5 mH/2 μF)Q = 50/16Q = 3.125
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