MGVCL Exam Paper (30-07-2021 Shift 1) દુર્ગતિ' શબ્દનો વિરુદ્ધાર્થી શબ્દ ક્યો છે? સુગતિ કુગતિ અદુર્ગતી સળંગગતિ સુગતિ કુગતિ અદુર્ગતી સળંગગતિ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Abolishid Wrinkel Various Absurrd Abolishid Wrinkel Various Absurrd ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) 1 terabyte is equal to 1024 bytes 1024 kilobytes None of these 1024 gigabytes 1024 bytes 1024 kilobytes None of these 1024 gigabytes ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The necessary equation to be solved during the load flow analysis using Fast-Decoupled methid is given below:where B' and B'' are formed using the imaginary part of the bus admittance matrix Ybus, n is the total number of buses in the system, m is the number of voltage regulated buses. The size of matrix B' is∆P/|Vi|= -B' ∆δ∆Q/|Vi| = -B'' ∆|Vi| (n-1) x (n-1) (n-m-1) x (n-m-1) (n-m) x (n-m) (m-1) x (m-1) (n-1) x (n-1) (n-m-1) x (n-m-1) (n-m) x (n-m) (m-1) x (m-1) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In FDLF method,B' corresponds to susceptance of unknown of PQ and PV busOrder of B' matrix is = (n -1)*(n - 1)Where n is total no. of buses.Order of B'' = (n - m - 1)*(n - m - 1)
MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following architectures is also known as "Five Principles of Peaceful Co-existence"? Manusmriti Panchsheel Vedanga Panchayatana Manusmriti Panchsheel Vedanga Panchayatana ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The current flowing to a balanced delta connected load through line 'a' is 15 A when the conductor of line 'b' is open. With the current in line 'a' as reference, compute the symmetrical components of the line currents. Assume the phase sequence of 'abc'. Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 - j13) AIa₂ = (7.5 + j13) A Ia₀ = 0 AIa₁ = (-7.5 - j13) AIa₂ = (-7.5 - j4.33) A Ia₀ = 0 AIa₁ = (7.5 + j4.33) AIa₂ = (7.5 - j 4.33) A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the given question,Ib = 0Ia = -IcCalculation:Ia1 = 1/3*(Ia + a*Ib + a²*Ic)= 1/3*(15 + 15∟-120°)= 7.5 + j*4.33 AIa2 = 1/3*(Ia + a²*Ib + a*Ic)= (1/3)*(15 + 15∟120°)= 7.5 - j*4.33 AIao = (1/3)*(Ia + Ib + Ic)= (Ia - Ia)= 0